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3 years ago

Why is the alpine tundra important to protect

2 answers:

6 0

Answer: the tundra is important to protect is that it serves as a habitat for migratory populations, like waterfowl, shorebirds, caribou and several bear species. It is home to endangered animals such as the Arctic Fox, Polar Bear, Grizzly Bear, Caribou, and Musk Ox.

Explanation:

slava [35]3 years ago

4 0

The tundra is important to protect because it acts as a carbon sink by absorbing carbon dioxide from the environment and helping to counteract the detrimental effects of carbon emissions.

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1. Once the action potential reaches the axon terminus, the information needed to be sent through the synapse to the muscle fibe

Sever21 [200]

Explanation:

Synapses are junctions at axon terminals where they connect to dendrites of other neurons at these junctions chemical reactions occur in order to facilitate the passage of information as chemical signals. There are several neuron types which include sensory motor and into neurons which bridge the two.

1. At neuromuscular junctions, electrical signals are transmitted:

The action potential travels along the membrane until the synapse where it’s electrical depolarization leads to the opening of channels allowing only sodium ions to enter
these flow through a presynaptic membrane until the concentration is built up, activating ion sensitive proteins attached to vesicles containing neurotransmitters like acetylcholine
this leads to changes in the proteins leading to the fusion with the membrane of the presynaptic cell, so vesicles are open and neurotransmitter is released. The neurotransmitter diffuses across to chemical receptors on the presynaptic cell where they bind temporarily. This increases the permeability of the sarcolema to Na+;a new action potential is generated

2. Contraction of the sarcomere occurs via several steps.

This action potential in the muscle, travels along T-tubules, and Ca+ ions are released by the sarcoplasmic reticulum into the sarcoplasm

Ca and troponin combine, pulling myosin filaments, exposing the actin filament's myosin binding sites
cross-bridge formation occurs, leading to the sliding of filaments.
ATP drives cross-bridge cycling while mysosin pulls on actin strands
muscle fibers shorten and contract
later ACH is degraded in the synapse. Na ions are not released, and the action potential is not transmitted.
the Ca channels on the SR close, while Ca is reabsorbed stopping Ca-troponin binding, closing myosin binding sites on actin and leading to cross bridge separation. The muscle fiber relaxes in their resting states.

Learn more about the autonomic nervous system at brainly.com/question/10386413

Learn more about neurotransmitters at brainly.com/question/9424160

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5 0

3 years ago

What would happen to species if it stopped reproducing?

meriva

Answer:

If animals stop reproduction, there will less variety, fewer food options and they will eat each other. There will be no meat for humans and eventually life will extinct from this planet.

Explanation:

8 0

3 years ago

Read 2 more answers

Imagine that you attempted to recreate Mendel's work with garden peas. You began by crossing true breeding violet-flowered, tall

salantis [7]

Answer:

(a) 90

(b) 30

(d) 10

F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation.

F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment

Explanation:

The F2 phenotypes are supposed to be in 9:3:3:1 according to Mendelian law. The total number of F2 progeny is: 80 + 36 + 39 + 5 = 160

(a) Hence, the expected number of tall, violet plants will be:

9/16 x 160 = 90

(b) Expected number of tall, white plants will be:

3/16 x 160 = 30

(d) Expected number of dwarf, white plants will be:

1/16 x 160 = 10.

Total number of tall F2 plants = 80 + 36 = 116

Total number of dwarf F2 plants = 39 + 5 = 44

Expected ratio of tall:dwarf plants according to Mendel = 3:1

Expected number of tall plants = 3/4 x 160 = 120

Expected number of dwarf plants = 1/4 x 160 = 40

Chi square $X^2$

= $\frac{(observed frequency - expected frequency)^2}{expected frequency}$

$X^2$ for tall = $\frac{(116 - 120)^2}{120}$

= 0.1333

$X^2$ for dwarf = $\frac{(44 - 40)^2}{40}$

= 0.40

Total $X^2$ = 0.1333 + 0.4

0.5333

Degree of freedom = n - 1

2 - 1 = 1

Tabulated $X^2$ (α = 0.05) = 3.841

Since the tabulated $X^2$ is more than the calculated $X^2$ , the hypothesis that the F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation is accepted.

Observed Expected $X^2$

tall, violet flowers 80 90 $\frac{(80-90)^2}{90} = 1.11$

tall, white flowers 36 30 $\frac{(36-30)^2}{30} = 1.2$

dwarf, violet flowers 39 30 $\frac{(39-30)^2}{30} = 2.7$

dwarf, white flowers 5 10 $\frac{(5-10)^2}{10} = 2.5$

Total 160 160 7.51

Degree of freedom = 4 - 1 = 3

Tabulated $X^2$ (α = 0.05) = 7.815

The tabulated $X^2$ value is more than the calculated $X^2$ value. Hence, F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment.

3 0

3 years ago

Write three characteristics of fungi

V125BC [204]

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