Answer:
Explanation:
The following code is written in Java. After finding the PP 11.1 file online I added the try/catch to the code as requested by the question. The program takes the input from the user, checks it's length, and if it contains more than 20 characters it throws the exception. This exception states that "the string has more than 20 characters" and then continues processing more strings until the user enters "DONE". The program has been tested and the output can be seen in the attached image below. Due to technical difficulties I have added the code as a txt file below.
Answer:
Please see the attached file for the complete answer.
Explanation:
I believe a block. I think that is the thing that can be repeated though the different parts of the code.
Answer:
#include <iostream>
using namespace std;
void printmultiples(int n) //function to print first five multiples between 3168 and 376020
{
int a =3168,c=1;
cout<<"First five multiples of "<<n<<" are : ";
while(a%n!=0 && a<=376020) //finding first mutiple of n after 3168.
{
a++;
}
while(c<6)//printing multiples.
{
cout<<a<<" ";
a+=n;
c++;
}
cout<<endl;
}
int main() {
int t,n;
cin>>t;//How many times you want to check.
while(t--)
{
cin>>n;
printmultiples(n);//function call..
}
return 0;
}
Input:-
3
15
43
273
Output:-
First five multiples of 15 are : 3180 3195 3210 3225 3240
First five multiples of 43 are : 3182 3225 3268 3311 3354
First five multiples of 273 are : 3276 3549 3822 4095 4368
Explanation:
I have used a function to find the first five multiples of the of the numbers.The program can find the first five multiples of any integer between 3168 and 376020.In the function I have used while loop.First while loop is to find the first multiple of the integer n passed as an argument in the function.Then the next loop prints the first five multiples by just adding n to the first multiple.
In the main function t is for the number of times you want to print the multiples.In our case it is 3 Then input the integers whose multiples you want to find.
