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Dmitriy789 [7]
3 years ago
9

Evaluate the equation 2L+6=6L-10

Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

2

Step-by-step explanation:

2L + 6 = 6L - 10                      Add 10 to both sides

2L + 6 + 10 = 6L                     Combine the left.

2L + 16 = 6L                           Subtract 2L from both sides

16 = 6L + 2L                           Combine the right    

16 = 8L                                   Divide by 8

8L = 16

8L/8 = 16/8

L = 2

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The two lines, P and Q, are graphed below: Line P is drawn by joining ordered pairs negative 8,15 and 6, negative 12. Line Q is
andreyandreev [35.5K]

Solution:

Keep in mind ,

Equation of line joining two points (a,b) and (p,q) is given by :

     \frac{q-b}{p-a}=\frac{y-b}{x-a}

Equation of line P which is obtained by  joining  (- 8,15) and (6, - 12) is given by:  

\frac{y-15}{x+8}=\frac{-12-15}{6+8}\\\\ 14(y-15)=-27(x+8)\\\\ 14 y -210= -27 x - 216\\\\ 27 x+14 y+6=0

Equation of line Q which is obtained by  joining  (4,16) and (-9, 10) is given by:  

\frac{y-16}{x-4}=\frac{16-10}{4+9}\\\\ 13(y-16)=6(x-4)\\\\ 13 y -208= 6 x - 24\\\\ 6 x-13 y+184=0

Equation of line P and Q are

27 x+14 y+6=0-------(1)× 2

6 x-13 y+184=0-------(2)× 9

54 x + 2 8 y+12=0---(1)

54 x -117 y +1656=0----(2)

(1) - (2)

145 y= 1644

y=11.33,

27 x+14 y+6=0-------(1)×13

6 x-13 y+184=0-------(1)×14

351 x + 182 y + 78=0-----(1)

84 x - 182 y +2576=0----(2)

(1) + (2)

435 x + 2654=0

x = - 6.11

So, solution set is (-6.11, 11.33)

Option (C) is true. (−2, 4), because this point makes both the equations incorrect.


8 0
3 years ago
Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589. Yo
stellarik [79]

Answer:

x = 18

Step-by-step explanation:

First, let's find the ratios between the two triangles

We'll use AV and AC

372 ÷ 589 = 12/19

All of the sides of the smaller triangle are 12/19 of the bigger triangle

Now let's find x

We know that AU + UB = AB

So it's 20x + 108 + 273 = AB

12/19 of a bigger triangle side equals a small triangle side

(12/19)AB = AU

For this equation multiply both sides by 19/12 to isolate AB

(12/19)AB x 19/12 = AU x 19/12

AB = (19/12)AU

Now we have this

20x + 108 + 273 = (19/12)(20x + 108)

20x + 381 = (19/12)(20x + 108)

Distribute the 19/12

20x + 381 = 95/3x + 171

Move all like terms to one side

20x + 381 = 95/3x + 171

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20x + 210 = 95/3x

- 20x           - 20x

Don't forget about common denominators

210 = 95/3x - 60/3x

210 = 35/3x

Multiply both sides by 3

210 x 3 = 35/3x x 3

630 = 35x

Divide both sides by 35

630/35 = 35x/35

x = 18

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