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Dmitriy789 [7]
3 years ago
9

Evaluate the equation 2L+6=6L-10

Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

2

Step-by-step explanation:

2L + 6 = 6L - 10                      Add 10 to both sides

2L + 6 + 10 = 6L                     Combine the left.

2L + 16 = 6L                           Subtract 2L from both sides

16 = 6L + 2L                           Combine the right    

16 = 8L                                   Divide by 8

8L = 16

8L/8 = 16/8

L = 2

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Consider the exponential function f ( x ) = 13 , 500 ⋅ 0.89^x, which models the value of Mikayla's scooter, where x represents t
Elden [556K]

Answer: $8470

Step-by-step explanation:

To solve this, you can substitute 4 for x:

f(x) = 13500*.89^4\\f(x) = 13500*0.6274\\f(x) = 8470

Mikayla's scooter is worth around $8470 after 4 years.

It was originally worth 13,500 dollars and depreciated by 11% every year.

7 0
3 years ago
Find 1/4+13/20<br> . Write your answer as a fraction in simplest form.
jek_recluse [69]
The LCD here is 20.  Thus, 1/4 = 5/20.  The sum of 5/20 and 13/20 is 18/20, which can be reduced to 9/10.
4 0
3 years ago
Two cylinders are similar. The volume of the larger cylinder is 343 ft³ and the volume of the smaller cylinder is 125 ​​ft³. The
andreev551 [17]
Both cylinder are similar
Volume of a cylinder is πr^2h
if we consider both has same radius as they are similar
Lets say V1 is volume of small cylinder and V2 is volume of big cylinder.
V1/V2=πr^2x5/πr^2xh
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6 0
3 years ago
Alex bikes 2 3/4 miles. Then, she runs 1 2/4 miles. The distance she bikes is how many times the distance she runs?
d1i1m1o1n [39]

Answer:

2 1/5

Step-by-step explanation:

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6 0
3 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
MrRa [10]

Answer:

<em> 85% level of the confidence interval is</em>

<em>(26.337, 26.662)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

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Mean of the sample x⁻ = 26.5

The Standard deviation of the Population = 2.7

85% level of the confidence interval is determined by

(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })

Critical value Z₀.₁₅ = 1.036

<em> 85% level of the confidence interval is determined by</em>

(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })

(26.9 -1.036 \frac{2.7}{\sqrt{295} } , 26.5 + 1.036 \frac{2.7}{\sqrt{295} })

( 26.5 - 0.1628 , 26.5+0.1628)

(26.3372,26.6628)

7 0
3 years ago
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