Answer:
55m^2
Step-by-step explanation:
The area of a rectangle is l x w (width x height)
We know that the length (l) of the rectangle is 6m longer than its width (w), then:
(1) l = w + 6
We also know that the perimeter of the rectangle is 32m, so:
(2) 2l + 2w = 32
Now substitute the value of l in (1) for l in (2):
2(w + 6) + 2w = 32
Distribute:
2w + 12 + 2w = 32
Combine like terms and subtract 12 from both sides:
4w = 20
Divide both sides by 4:
w = 20/4 = 5 (so the width is 5m)
Find the length (use (1)):
l = 5 + 6 = 11m (length of rectangle)
Then, the area is:
A = l x w = 5 x 11 = 55m^2
Answer:
A° = 44.42°
Step-by-step explanation:
Soh Coh Toa
Soh: sin(theta) = Opp/Hyp
Coh: cos(theta) = Adj/Hyp
Toa: tan(theta) = Opp/Adj
We are using Coh: cos(theta) = Adj/Hyp because we need to find Angle A and that 5 is Adjacent and 7 is the Hypotenuse.
cos(A°) = 5/7
A° = cos^-1 (5/7)
A° ≈ 44.4153086
A° = 44.42°
Answer:
The answer is 357
Step-by-step explanation:
<h3>Answer: Choice A) x+14</h3>
=======================================
Work Shown:
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (f(x)) - (g(x))
(f-g)(x) = (3x+10) - (2x-4)
(f-g)(x) = 3x+10 - 2x+4
(f-g)(x) = (3x-2x) + (10+4)
(f-g)(x) = x+14
The image of the labeled spinner isn't attached
Answer:
Kindly check explanation
Step-by-step explanation:
Answering hypothetically ;
First create a sample space using the label of the two spinners ;
Each space will be the sum of the possible number that shows up on each turn of the spinner.
From the sample space, count the number of spaces where, the sun is greater than 4, that is the required outcome ; = x
Then the total number of samples in the sole space = total possible outcomes = y
Hence,
P(obtaining a sum greater than 4) = required outcome / Total possible outcomes
= x / y
