__ involves having a variety of investments in your _

There are 48 students in a school play. The ratio of boys to girls is 5:7. How many boys are in the school play? Explain how you

mr Goodwill [35]

Boys: x
gilrs: y

From the text of the task:

$\left \{ {{\frac{x}{y}=\frac{5}{7}} \atop {x+y=48 \rightarrow x=48-y}} \right.$

Replacing x:

$\frac{48-y}{y}=\frac{5}{7}\\
\\
7(48-y)=5y\\
\\
336-7y=5y\\
\\
12y=336\\
\\
y=\frac{336}{12}=28$

So there are 28 girs and 20 boys

7 0

4 years ago

Read 2 more answers

Solve for z 7z < 21 z=

Step2247 [10]

Answer:

z=5

Step-by-step explanation:

3 0

3 years ago

Use special right triangles to solve for the exact value of x. 4 9 16

Gelneren [198K]

Answer: A basic theorem for finding the third length of a right angle triangle is the Pythagoras Theorem.

In a right angle triangle, the slant and usually longest side is called the Hypotenuse while the other two sides are Opposite and Adjacent.

The Pythagoras Theorem States:

$hypotenuse^{2} = opposite ^{2} + adjacent ^{2}$

Step-by-step explanation:

If for example, we are given the other two sides as 3 and 4 respectively,

Using

$Hyp^2=Opp^2+Adj^2$

$Hyp^2 =3^2+4^2=25$

Hypotenuse = $\sqrt{25}$ =5

These set of numbers (3,4,5) in this that satisfies the theorem are called Pythagorean Triples

7 0

3 years ago

Small scooters cost £80 and large scooters cost £130. A school buys few scooters for the playground for £1000. How many of the s

Sonbull [250]

Answer:

Small scooters = 6

Large scooters = 4

Step-by-step explanation:

Let S represents small scooter and L represents large scooter

The cost of a small scooter is £80

Mathematically, the cost of S number of small scooters is

80S

The cost of a large scooter is £130

Mathematically, the cost of L number of large scooters is

130L

The total amount spent on both scooters is £1000

Mathematically,

80S + 130L = 1000

So we have 2 unknowns and only 1 equation. Therefore, we have use trial and error method .

Trial and Error Method:

80S + 130L = 1000

80S = 1000 - 130L

S = (1000 - 130L)/80

Let’s suppose they bought 1 large scooter

S = (1000 - 130(1))/80

S = 10.875

Number of scooters cannot be in fraction so 1 doesn’t work

Let’s suppose they bought 2 large scooter s

S = (1000 - 130(2))/80

S = 9.25

Number of scooters cannot be in fraction so 2 doesn’t work

Let’s suppose they bought 3 large scooter s

S = (1000 - 130(3))/80

S = 7.625

Number of scooters cannot be in fraction so 3 doesn’t work

Let’s suppose they bought 4 large scooters

S = (1000 - 130(4))/80

S = 6

So that means they bought 6 small scooters and 4 large scooters.

Similarly, other combinations for scooters don’t work since they yield either fractional value or negative value which cannot be correct.

Therefore, the only possible combination of small and large scooters is

6 Small scooters

4 Large scooters

Verification:

80S + 130L = 1000

80(6) + 130(4) = 1000

480 + 520 = 1000

1000 = 1000 (satisfied)

8 0

4 years ago

The table shows the number of blue marbles and red marbles that four friends have collected,

evablogger [386]

The lowest ratio is Lucian

7 0

3 years ago

Read 2 more answers

__ involves having a variety of investments in your __

involves having a variety of investments in your