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butalik [34]
2 years ago
7

Please help!

Mathematics
1 answer:
zepelin [54]2 years ago
5 0

9514 1404 393

Answer:

  14 minutes

Step-by-step explanation:

Let t represent the time it took Suki to pick out her pumpkin. The given relation is ...

  10t -13 = 127 . . . . . equation for minutes to carve

  10t = 140 . . . . . . . . add 13

  t = 14 . . . . . . . . . . divide by 10

It took Suki 14 minutes to pick out her pumpkin.

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Match each system of linear equations with the correct number of solutions
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Answer:

Hey there!

The first equation has no solutions, as it is parallel lines.

The second equation has infinitely many solutions, as it is basically the same line, and the two lines intersect at infinite points.

The third equation is just one solution.

Let me know if this helps :)

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0

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Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

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Korvikt [17]

Answer:C

Step-by-step explanation:on edge

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