Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
__
We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
![\left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C1%2B2%261-3%261-1%261000%2829%2B1%29%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C3%26-2%260%2630000%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D)
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
Answer: try to (x) each one by the answer to -0.0035 +70
Step-by-step explanation:
Answer:
17
Step-by-step explanation:
They are vertical angles so they are the same angle.
51 = 3x
Divide each side by 3
17 = x
You need to DIVIDE the 3/4 meter into 1/3 meter pieces, so....
(3/4)÷(1/3) = (3/4) *(3/1) = (9/4) = 2.25
She can cut 2 (1/3) meter pieces.
To find what is left subtract (2/3) from the original (3/4).
(3/4)-(2/3)= (1/12) meter
Answer:
The length of diagonal BD is 11·(1 + √3)
The length of diagonal AC = 22
Step-by-step explanation:
The given data are;
Quadrilateral ABCD = A kite
The length of segment AD = 22
The measure of ∠DAE = 60°
The measure of ∠BCEE = 45°
Whereby, triangle ΔADE = A right triangle, and DE is the perpendicular bisector of AC, by trigonometric ratio, we have;
AE = EC
DE = 22 × sin(60°) = 11·√3
AE = 22 × cos(60°) = 11
∴ AE = EC = 11
BE = EC × tan(∠BCE) = 11 × tan(45°) = 11
The length of the diagonal BD = BE + DE (By segment addition property)
∴ BD = 11 + 11·√3 = 11·(1 + √3)
The length of diagonal BD = 11·(1 + √3)
The length of diagonal AC = AE + EC
∴ AC + 11 + 11 = 22
The length of diagonal AC = 22.
