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Nady [450]
3 years ago
10

Please look over WILL MARK BRAINLIEST!! Must answer both questions or your answer will be reported.

Mathematics
2 answers:
Bas_tet [7]3 years ago
6 0

Answer:

Question 5:  1024\pi\ m^2; Question 6: False

Step-by-step explanation:

Question 5:

A=r^2\pi\\\\d=2r\\\\64=2r\\\\r=32\\\\A=32^2\pi\\\\A=1024\pi

Question 6:

A=r^2\pi\\\\d=2r\\\\12=2r\\\\r=6\\\\A=6^2\pi\\\\A=36(3.14)\\\\A=113.04

nikitadnepr [17]3 years ago
4 0

Answer:

1. D. 1024pi m²

2. False

Step-by-step explanation:

Radius = 64/2 = 32

Area = pi × 32²

= 1024pi m²

Radius = 12/2 = 6

= 3.14 × 6²

= 113.04 cm²

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Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

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