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Andre45 [30]
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
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You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
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I like to use a graphing calculator for problems like this.
First lets solve for x we know 3x=90. In this case x=30. Now we can solve for y. We know the triangle needs to equal 180 so y+2(30)=180. So we get y=120. Hope it helps
Answer:
68x + 36y
General Formulas and Concepts:
- Order of Operations: BPEMDAS
- Combining like terms
Step-by-step explanation:
<u>Step 1: Define expression</u>
(19x + 4y) + (49x + 32y)
<u>Step 2: Simplify expression</u>
- Combine like terms (x): 68x + 4y + 32y
- Combine like terms (y): 68x + 36y
Answer:
368m
Step-by-step explanation:
16 x 20 = 320
8 x 12 x 1/2 = 48
Add them together and get 368
Answer:

Step-by-step explanation:


