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faust18 [17]
3 years ago
6

5. Rectangle ABCD is graphed in the coordinate plane. The following are vertices of the rectangle: A(-1,-6), B(-1,-7), C(1,7), a

nd D(1,-6). Given these coordinates, what is the length of side AB in this triangle? On the lines below, provide the length of the side as well as your reasoning for how you arrived at your answer.​
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

The legnth of side AB would be 3 units

Step-by-step explanation:

First, you would determine that both point A and point B would have the same y-coordinate of 1.   Then you would determine the difference between the x values of points A and B.  Since 5 (the x-value for B) minus 2 (the x-value for A) is 3, the legnth of side AB would be 3 units.

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What is the value of n in the equation 1/2(n – 4) – 3 = 3 – (2n + 3)?
ozzi
(1/2)(n - 4) - 3 = 3 - (2n + 3
Distribute the (1/2) on the left and the -1 on the right.
(1/2)n - 2 - 3 = 3 - 2n - 3
Combine like terms.
(1/2)n - 5 = -2n
Add 2n to both sides and add 5 to both sides
2.5n = 5
Divide both sides by 2.5
n = 2
6 0
3 years ago
You bought a car for $19,999 and your bank requires 10% down. How much money is
valkas [14]

Answer:

  $17,999.10

Step-by-step explanation:

Let x represent the amount the bank will lend.

  x = $19,999(1 -10%) = 0.90($19,999) = $17,999.10

The bank is willing to lend $17,999.10 on the car.

6 0
3 years ago
Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
This net will be folded to form a prism.
Grace [21]

Answer:

it is a and c and b and e and also and f

Step-by-step explanation:

7 0
3 years ago
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There are 1,400 students in a school. A random sample of 50 students contains 7 students with birthdays in March. Based on the d
creativ13 [48]

Answer: 196 students should have birthdays in March

Step-by-step explanation: you do 1400 divided by 50 which is 28. Then you do 28 times 7 which is 196.

Hope this helped have a great day/night!!!

5 0
3 years ago
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