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3 years ago

This box is 3/4 inch long, 1/2 inch wide, and 1 /4inch deep. What is the volume of the box?

Mathematics

2 answers:

Aliun [14]3 years ago

8 0

Answer:

Volume = 3/4 x 1/2 x 4 = 3/2 inches³

dedylja [7]3 years ago

5 0

The volume of the box is 0.09375 inches cube.

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Can somebody solve this please?

11111nata11111 [884]

Answer:

220

Step-by-step explanation:

Now, I'm not sure if 220 is correct, but I'll explain my reasoning.

We know three angles of a triangle add up to 180 degrees.

So, the smaller triangle has 70 degrees and a and b variables. By virtue, a + b + 70 = 180.

So, a + b = 110.

Likewise, when you look at the whole triangle, 70 degrees is also one of the angles while c and d are unknown.

So, c + d + 70 = 180.

This means c + d = 110.

So, (a + b ) + (c + d ) =

110 + 110 =

220 degrees.

I hope this helps!

4 0

2 years ago

Read 2 more answers

2. If y = V9 – 3x, determine the value of x for which y will be a real number.

Pepsi [2]

Answer:

x ≤ 3

Step-by-step explanation:

The expression inside the radical ≥ 0, thus

solve

9 - 3x ≥ 0 ( subtract 9 from both sides )

- 3x ≥ - 9

Divide both sides by - 3, reversing the symol as a result of dividing by a negative quantity

x ≤ 3

Any value of x less than or equal to 3 ensures $\sqrt{9-3x}$ is real

8 0

3 years ago

Can some PLEASE HELP ME I

erastova [34]

Answer:

Step-by-step explanation:

because the equation when you get it is the number you divide with

6 0

3 years ago

may runs 10 / 4 miles every day after school. Beth says that she runs farther than may every day because she runs 5 / 2 miles ev

Salsk061 [2.6K]

They run the same amount. 5/2 is 10/4 simplified.

7 0

3 years ago

Read 2 more answers

The surface area of the prism is

Shtirlitz [24]

Surface area is the area of all the surfaces, that's why it's called surface area...so let's calculate the area of the bottom rectangle, the front rectangle, back rectangle, and the two triangles on the sides.

Bottom Rectangle:

$\sf A=lw$
Length = 12 yd, Width = 9 yd

$\sf A=(12)(9)$

$\sf A=108~yd^2$

Front Rectangle:

$\sf A=lw$
Length = 12 yd, Width = 5 yd

$\sf A=(12)(5)$

$\sf A=60~yd^2$

Back Rectangle:

$\sf A=lw$
Length = 12 yd, Width = 8 yd

$\sf A=(12)(8)$

$\sf A=96~yd^2$

Triangle:

$\sf A=\dfrac{1}{2}bh$
Base = 9 yd, Height = 4 yd

$\sf A=\dfrac{1}{2}(9)(4)$

$\sf A=12~yd^2$

Remember we have two of these triangles.

Now let's add up all the measurements:

$\sf 108+60+96+12+12=\boxed{\sf 288~yd^2}$

7 0

4 years ago