<span>Square root of y^2 = y
so
</span><span>Square root of y^2 times y^2 = y * y^2 = y^3
answer
y^3</span>
Answer:
Rectangle 1 area: 53 units squared
Shape 2 area: 43.75 units squared
Step-by-step explanation:
Shape 1:
We need to find the area of the two triangles in this rectangle and subtract it from the total area of the rectangle.
Total area of the rectangle:
13 * 5 = 65
Area of triangles (they are congruent):
1/2 * 4 * 3 = 6
6 * 2 = 12
65 - 12 = 53
The area of the shaded part is 53 (I don't know what your unit of measurement is. Just say units.)
Shape 2:
First, let's find the area of the parallelogram at the top.
10 * 3 = 30
Now, let's find the area of the rest of the shape. Triangle first...
1/2 * 4 * 1.5 = 3
Now, the rectangle and the tiny triangle we can section out at the end:
7 * 1.5 = 10.5 + 1/4 (Triangle) or 0.25 = 10.75
Total area: 10.75 + 3 + 30 = 43.75
</h2><h2>3.</h2><h2>
</h2><h2>Hope it Helps❤</h2>
![[4^{(2-5)}].[g^{(3-12)}].[p^{-2}].[m^{5}]](https://tex.z-dn.net/?f=%5B4%5E%7B%282-5%29%7D%5D.%5Bg%5E%7B%283-12%29%7D%5D.%5Bp%5E%7B-2%7D%5D.%5Bm%5E%7B5%7D%5D)
![[4^{-3}].[g^{-9}].[p^{-2}].[m^{5}]](https://tex.z-dn.net/?f=%5B4%5E%7B-3%7D%5D.%5Bg%5E%7B-9%7D%5D.%5Bp%5E%7B-2%7D%5D.%5Bm%5E%7B5%7D%5D)
or 