1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pepsi [2]
3 years ago
5

If the perimeter of a rectangle is 124cm & the width is 35cm, what is the length?

Mathematics
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

l=27

b=2×35=70

2l=124-70=54

l=54/2=27

You might be interested in
Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o
tatyana61 [14]

Answer : 96

x – y = 16 --------> equation 1

1/8 x + 1/2 y = 52

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

1/8 x + 1/2 ( -16 + x ) = 52

1/8x - 8 + 1/2 x = 52

1/8x + 1/2x - 8 = 52

Take common denominator to combine fractions

1/8x + 4/8x -8 = 52

5/8x - 8 = 52

Add 8 on both sides

5/8x = 60

Multiply both sides by 8/5

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

8 0
3 years ago
What is the range of this function?
Bad White [126]

The range is the set of all y-coordinates.

R = {2, 6, 8}

4 0
3 years ago
Darcy, Jason, and Maria share $268. Jason has $20 more then Darcy
aleksandr82 [10.1K]

Answer:

Darcy and Jason have $124 combined

Step-by-step explanation:

8 0
4 years ago
Reports on a student’s ACT, SAT, or MCAT usually give the percentile as well as the actual score. The percentile is just the cum
DaniilM [7]

Answer:

The percentile is calculated with the following probability:

P(X

And using the z score we got:

P(X

So then we can conclude that 31 represent approximately the percentile 81 on the distribution given

He scored better than about 80.98 % of all MCAT takers.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(25.3,6.5)  

Where \mu=25.3 and \sigma=6.5

And for this case we have a score of 31

The percentile is calculated with the following probability:

P(X

And using the z score we got:

P(X

So then we can conclude that 31 represent approximately the percentile 81 on the distribution given

He scored better than about 80.98 % of all MCAT takers.

6 0
3 years ago
What is 2+6*5/8 ? I need help with this math problem , thank you.
vampirchik [111]

Hey.

I hope that you're familiar with P.E.M.D.A.S :)

applying PEMDAS :

2 + 6 × 5 ÷ 8

2 + 30 ÷ 8

32 ÷ 8 = 4

Hence, The required answer is 4

Thanks.

8 0
3 years ago
Read 2 more answers
Other questions:
  • Can someone show me how to do this?
    13·1 answer
  • What is 6/12 + 3/12 + 4/12+1 8/12+2 9/12?Please turn into mixed number
    12·2 answers
  • What is multiplication in 2 paragraphs
    8·2 answers
  • What is the first step needed to solve 3 over 4 multiplied by x minus 3 equals negative 18 ? (1 point)
    6·1 answer
  • Help please pleseee
    8·1 answer
  • Plz answer<br> WILL GIVE BRAINLIEST
    15·2 answers
  • Write the expanded form of the expression<br> y(0.25 +6)
    5·1 answer
  • Is there a relationship between the percent of high school graduates in each state who took the SAT and the state’s mean SAT Mat
    13·1 answer
  • Plsplspslpslplspslpslsplsplsplsplsplspsl
    11·1 answer
  • I can’t figure this out I need the answer
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!