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saveliy_v [14]
3 years ago
7

Y=x+5 4x+y=20 Solving system by substitution

Mathematics
1 answer:
sineoko [7]3 years ago
3 0
Y = x + 5....so we sub in x + 5 for y in the other equation

4x + y = 20
4x + x + 5 = 20
5x + 5 = 20
5x = 20 - 5
5x = 15
x = 15/5
x = 3

y = x + 5
y = 3 + 5
y = 8

solution is (3,8)
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maks197457 [2]
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So,

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Let f(t)=2\sin(2t+3)^2. With n=4, we're looking for coefficients c_i and nodes x_i, with 1\le i\le4, such that

\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx c_1f(x_1)+\cdots+c_4f(x_4)

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Using the quadrature, we then have

\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.3749f(-0.8611)+0.6521f(-0.3400)+0.6521f(0.3400)+0.3749f-0.8611)
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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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