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Gennadij [26K]
2 years ago
11

Mrs. Diaz had 5/6 gallon of paint to start. When she finished sha had 1/2 gallon. How much paint did Mrs. Diaz use?​

Mathematics
1 answer:
exis [7]2 years ago
4 0

Answer:

1/3

Step-by-step explanation:

To get the amount of paint,you will have to deduct the number of paint she used to start minus the amount of of gallon she finished with.

5/6-1/2

L.C.M

10-6/12

4/12

=1/3

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OK.  Hold on tight.  Here we go.
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Answer:

Step-by-step explanation:

<h3>Solving linear equation with one variable:</h3>

   1) -4 + 3x = 4x - 8

        Add 4 to both sides

      -4 + 3x + 4 = 4x - 8 +  4

               3x     = 4x - 4

Subtract 4x from both sides,

        3x - 4x = -4x + 4x - 4

              -x   = -4

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2) -5x - 8 = 2

Add 8 to both sides

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Divide both sides by (-5)

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3) 12r - 14 = 5(2-r)

    12r - 14 = 5*2 - 5*r

     12r - 14 = 10 - 5r

Add 14 to both sides

 12r - 14 + 14 = 10 - 5r + 14

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Add 5r to both sides

        12r + 5r = 24

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Divide both sides by 17

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      3x + 2x = -9

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              \sf \dfrac{5}{5}x=\dfrac{-9}{5}\\\\\boxed{x = \dfrac{-9}{5}}

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2 years ago
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Describe 2 different ways7/3 as a mixed number
topjm [15]
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1) ⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
2 and 1/3 (which is also written as 2 1/3)
⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆

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⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆


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Consider the question of whether the home team wins more than half of its games in the National Basketball Association. Suppose
spayn [35]

Answer:

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The home team therefore wins 50% of its games

This means that p = 0.5

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Sample of 80 means that n = 80 and, by the Central Limit Theorem:

\mu = p = 0.65

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5*0.5}{80}} = 0.0559

This probability is 1 subtracted by the pvalue of Z when X = 0.65. So

Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{s}

Z = \frac{0.65 - 0.5}{0.0559}

Z = 2.68

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1 - 0.9963 = 0.0037

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Answer:

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