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Misha Larkins [42]

3 years ago

6

PLEASE HELP!!!!!!! ( Calculate the value of the expression )

2 answers:

blondinia [14]3 years ago

8 0

Answer:

The correct answer is -76.

Step-by-step explanation:

The step-by-step solution is shown in the image provided here, I hope it will help.

Alona [7]3 years ago

5 0

Answer:

<h2>-75</h2>

Step-by-step explanation:

<h3 /><h3>4 (8 - 10 • 3) + 2³ - 5)</h3><h3>= 4 ( 8 - 30) + 2³ - 5)</h3><h3>= 4 (-22) + 2³ - 5)</h3><h3>= 4 (-22) + 8 - 5)</h3><h3>= -88 + 8 - 5</h3><h3>= -80 - 5</h3><h3>= -75</h3>

$\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}$

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Marcy is making a hooked circle-shaped rug for her mother. The circumference of the circle-shaped rug is 69.08 inches.

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3 years ago

The exponential function f(x) = 3(5)x grows by a factor of 25 between x = 1 and x = 3. What factor does it grow by between x = 5

Delvig [45]

Answer:

B) 25

Step-by-step explanation:

Given exponential function:

$f(x)=3(5)^x$

The growth factor between $x=1$ and $x=3$ is 25.

To find the growth factor between $x=5$ and $x=7$

Solution:

The growth factor of an exponential function in the interval $x=a$ and $x=b$ is given by :

$G=\frac{f(b)}{f(a)}$

We can check this by plugging in the given points.

The growth factor between $x=1$ and $x=3$ would be calculated as:

$G=\frac{f(3)}{f(1)}$

$f(3)=3(5)^3$

$f(1)=3(5)^1$

Plugging in values.

$G=\frac{3(5)^3}{3(5)^1}$

$G=\frac{(5)^3}{(5)^1}$ (On canceling the common terms)

$G=(5)^{(3-1)}$ (Using quotient property of exponents $\frac{a^b}{a^c}=a^{(b-c)}$ )

$G=(5)^{2}$

∴ $G=25$

Similarly the growth factor between $x=5$ and $x=7$ would be:

$G=\frac{f(7)}{f(5)}$

$f(7)=3(5)^7$

$f(5)=3(5)^5$

Plugging in values.

$G=\frac{3(5)^7}{3(5)^5}$

$G=\frac{(5)^7}{(5)^5}$ (On canceling the common terms)

$G=(5)^{(7-5)}$ (Using quotient property of exponents $\frac{a^b}{a^c}=a^{(b-c)}$ )

$G=(5)^{2}$

∴ $G=25$

Thus, the growth factor remains the same which is =25.

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Step-by-step explanation:

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