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igor_vitrenko [27]
3 years ago
9

Help pls thanks again sorry to all people that is getting disturbed

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:

Just follow the arrow or see answer in each box

Step-by-step explanation:

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Complete the statement. [Type your answer as a number.]<br><br> 7 pounds × 16 ounces
k0ka [10]

Answer:

1792

Step-by-step explanation:

1 pound = 16 ounces

7 x 16 x 16

= 7 x 16^2

= 7 x 256

= 1792

8 0
2 years ago
Please help if you can! Thank you!
oksano4ka [1.4K]

Answer:

y = 2(x²+3x)

Step-by-step explanation:

3 0
2 years ago
I WILL MAKE YOU BRAINLIEST
34kurt

Answer:

40

Step-by-step explanation:

32/4=8

8 is 2x 4 so multiply 5x2=10

now multiply 10x4

7 0
2 years ago
Read 2 more answers
An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars over domestic. Step 2 of 2 : S
ziro4ka [17]

Answer:

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Sample of 421 new car buyers, 75 preferred foreign cars. So n = 421, \pi = \frac{75}{421} = 0.178

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.151

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.205

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

8 0
2 years ago
It takes 36 nails to weigh one pound. How many nails would it take to weigh 7 wholes and 2/3 pounds?
o-na [289]
36 * 7  gives you the number of nails in the whole pounds
36 * 2/3 gives you the fraction part

7 * 36 = 252
2/3 * 36 = 24

Total nails = 252 + 24 = 276 nails
5 0
2 years ago
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