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Dmitrij [34]
3 years ago
15

4.

Mathematics
1 answer:
Svetach [21]3 years ago
5 0

Answer:

A. b2 – 4ac = 0

Step-by-step explanation:

Hey user☺☺

Option a is correct

Because the graph has only one solution.

As the graph touches the x-axis at one point that means that it will have only one solution for x. But we know that a quadratic equation has two solutions. So the graph will have two equal solution and therefore the discriminant will be 0.

Hope this will help☺☺

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This is one question. Algebra 2 transformations
Talja [164]

Answer:

End result is ln(-x) + 1

Step-by-step explanation:

1,  ln x + 2

2. ln(x + 2) + 2

3. ln(x + 2 - 2) + 2 = ln x + 2

4. ln x + 1

5. ln(-x) + 1

8 0
3 years ago
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Help? :3 Tysm if you do xD
Montano1993 [528]

The answer is A because 13 times 6 equals 78

8 0
3 years ago
I WILL GIVE BRAINLIEST TO WHO EVER TELLS ME THIS ANSWER ASAP
blondinia [14]

it is not because prime factorization is a number broken down by its prime factors

4 x 3 x 20 x 8 x 22 = 42240

the correct prime factorization of 42240 is  2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 5 x 11


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4 0
3 years ago
A bank features a savings account that has an annual percentage rate of 3.5% with interest compounded quarterly. Vanessa deposit
vazorg [7]

Answer:

APY = 0.04 or 4%

Step-by-step explanation:

Given the annual percentage rate of 3.5% that is compounded quarterly, and a principal of $6,500:

We can use the following formula to solve for the annual percentage yield (APY):

APY =  (1 + \frac{r}{n})^n - 1

where <em>r</em> = interest rate = 3.5% or 0.035

<em>           n</em> = number of compounding periods per year = 4

We can plug in the values into the equation:

APY =  (1 + \frac{r}{n})^n - 1

APY =  (1 + \frac{.035}{4})^4 - 1

APY =  (1 + 0.00875)^4 - 1

APY =  (1.00875)^4 - 1

APY = 1.03546 - 1  

APY = 0.04 or 4%        

8 0
3 years ago
For each of the functions below, indicate whether the function is onto, one-to-one, neither orboth. If the function is not onto
Karo-lina-s [1.5K]

Answer:

f_{1} :Z \rightarrow Z is one to one mapping, it is not onto mapping

Step-by-step explanation:

f_{1} :Z \rightarrow Z\\ f_{1} (x) = x^{3}

f₁(x) is one to one mapping

Let x, y \epsilon Z

f₁(x) = f₁(y):

x₁³ = y₁³

f₁(x) is not onto mapping

Example: If f₁(x) = 7,

x₁³ = 7

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x₁ is not an element of Z

f_{1} :Z \rightarrow Z is one to one mapping, it is not onto mapping

5 0
3 years ago
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