How do you find the range of (x^3+x^2-6x)/(4x^2+4x-8) algebraically?

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

6 0

Answer:

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Step-by-step explanation:

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(100 points!)

tatyana61 [14]

Every 10 minutes of reading my book, I read 20 pages each. // part B you read 0.5 minutes per page

5 0

3 years ago

98 Points !! These are follow up according to previous question that had been answered for me. Help would be appreciated ! :))

IgorLugansk [536]

That's a copy of the figure from the other post; I didn't look at the answer.

We have Start(0,0)

$A(-16.55\cos 25, -16.55 \sin 25)$

$B=A+(5 \cos 53, 5 \sin 53)$

$C=B+(20,0)$

$C=(-16.55\cos 25 + 5 \cos 53+20, -16.55 \sin25 - 5 \sin 53)$

$C \approx (8.00968, -10.9875) \approx(8,-11)$

Your team takes the direct path at a constant speed of 6 miles per hour.

Our team. $T=\sqrt{8^2+11^2}/6 = 2.27 \textrm{ hours}$

Team Red follows the riddle and travels at 8 mph from Start to Post A, 9 mph from Post A to Post B, and 11 mph from Post B to Finish.

$T=16.55/8 + 5/9 + 20/11 = 4.44 \textrm{ hours}$

Team Blue follows the riddle and travels at a constant speed of 10 mph.

 $T=(16.55 + 5 + 20)/10 = 4.155 \textrm{ hours}$

Team Yellow follows the riddle and travels at a constant speed of 11 mph, but stops at Post A for 30 minutes and stops again at Post B for another 30 minutes.

$T=(16.55 + 5 + 20)/11 + 30/60 + 30/60=4.78 \textrm{ hours}$

Winner: our team, then Blue, then Red, then Yellow

3 0

3 years ago

What number must you add to the expression below to complete the square? x^2-20x?

polet [3.4K]

We have that
x²-20x
Group terms that contain the same variable
(x²-20x)
Complete the square
(x²-20x+10²)------> (x-10)²

the answer is
the number must be 100

5 0

3 years ago

WHAT IS A EQUATION PLEASE HELP!

nadya68 [22]

Answer: 1.5s+20

Step-by-step explanation:

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2 years ago

An example of consecutive odd integers is 23, 25, 27, and 29. Find four consecutive odd integers with a sum of 160. Show your wo

Andrew [12]

Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.

Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.

Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7

Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18

Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.

Answer: 37,39,41,43

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3 years ago