3 years ago

2^l-3x=1/64 Solve for l

Mathematics

1 answer:

serious [3.7K]3 years ago

3 0

$2^l-3x=\dfrac{1}{64}\\2^l=\dfrac{1}{64}+3x\\
l=\log_2\left(\dfrac{1}{64}+3x\right)$

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