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3 years ago

9

×² × ×⁴=×²+⁴ find the ×

1 answer:

Orlov [11]3 years ago

3 0

You have to do X to the power of two times X to the power of four and multiply that by itself and then multiply X to the power of 2+4 by itself to find the X

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In the figure above, quadrilateral ABCD is a parallelogram. Let x represent the measure of angle GBF, y represent the measure of

ira [324]

Answers:
measure angle x = 40°
measure angle y = 35°
measure angle z = 55°

Explanation:
Part (a): getting angle x:
In triangle BED, we have:
measure angle BED = 90°
measure angle BDE = 50°
Therefore:
measure angle DBE = 180 - (90+50) = 40°
Now, we have angle DBE and angle GBF vertically opposite angles.
This means that they are both equal. Therefore angle GBF = 40°
Since angle GBF is x, therefore:
x = 40°

Part (b): getting angle y:
We know that the sum of measures of angles on a straight line is 180.
This means that:
angle GBF + angle GBC + angle CBE = 180
We have:
angle GBF = 40°
angle GBC = 105°
angle CBE = y
Therefore:
40 + 105 + y = 180
y = 35°

Part (c): getting angle z:
In triangle BCE, we have:
measure angle BCE = z
measure angle BEC = 90°
measure angle CBE = 35°
Therefore:
z + 90 + 35 = 180
z = 55°

Hope this helps :)

8 0

3 years ago

Select each answer that is true

levacccp [35]

Answer:

rational

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLEASEE HELPP ANYONE

jeka57 [31]

Your best bet would be D.

3 0

3 years ago

Read 2 more answers

Solve.<br> logx + log6 (x - 1) =1<br> x =

strojnjashka [21]

X=2 . HOPE THIS HELPED !!!!

5 0

3 years ago

Need math help (last one wouldn't let me upload pic)

Scrat [10]

Answer:

$\text{Area of the figure}=54\text{ unit}^2$

Step-by-step explanation:

Please find the attachment.

Let us divide our given image in several parts and then we will find area of different parts.

First of all let us find the area of our red rectangle with side lengths 6 units and 7 units.

$\text{Area of rectangle}=\text{Length*Width}$

$\text{Area of red rectangle part}=6\text{ units}\times 7\text{ units}$

$\text{Area of red rectangle part}=42\text{ units}^2$

Now let us find area of yellow triangle on the top of red rectangle. We can see that base of triangle is 6 units and height is 1 unit.

$\text{Area of triangle}=\frac{1}{2}\times \text{Base*Height}$

$\text{Area of triangle}=\frac{1}{2}\times \text{6 units *1 unit}$

$\text{Area of triangle}=3\text{ unit}^2$

Let us find the area of green triangle.

$\text{Area of green triangle}=\frac{1}{2}\times \text{3 units *2 units}$

$\text{Area of green triangle}=3\text{ unit}^2$

Now we will find the area of blue triangle, whose base is 6 units and height is 2 units.

$\text{Area of blue triangle}=\frac{1}{2}\times \text{6 units *2 units}$

$\text{Area of blue triangle}=6\text{ units}^2$

Let us add all these areas to find the area of our figure.

$\text{Area of the figure}=42\text{ units}^2+3\text{ unit}^2+3\text{ unit}^2+6\text{ unit}^2$

$\text{Area of the figure}=(42+3+3+6)\text{ unit}^2$

$\text{Area of the figure}=54\text{ unit}^2$

Therefore, area of our given figure is 54 square units.

3 0

3 years ago