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Assoli18 [71]
3 years ago
10

You’re about to get on a plane to Seattle. You want to know if it’s raining. You call 3 random friends who live there and ask ea

ch if it’s raining. Each friend has a 2/3 chance of telling you the truth and a 1/3 chance of messing with you by lying. All 3 friends tell you that ""Yes"" it is raining. What is the probability that it’s actually raining in Seattle?
Mathematics
1 answer:
Lyrx [107]3 years ago
3 0

Answer:

The probability that it is actually raining in Seattle is 26/27

Step-by-step explanation:

Here we have the probability that a friend is telling the truth = 2/3

The probability that a friend is telling a lie = 1/3

Therefore, if all three friends say "Yes" it is raining in Seattle, the probability that is actually raining is given by the probability that one of them is telling the truth. That is the complement that all are messing with their friend.

The probability that all are not telling the truth is;

P(All not telling the truth) = \frac{1}{3} \times \frac{1}{3}   \times  \frac{1}{3}  =  \frac{1}{27}

P(One is telling the truth) = 1 - P(All not telling the truth)  = 1- \frac{1}{27} = \frac{26}{27}

Therefore, the probability that it is actually raining in Seattle = 26/27.

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We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.

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