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3 years ago

Plz answer to this question

Chemistry

1 answer:

NeX [460]3 years ago

6 0

Answer:

A is solid

B is solid

C is liquid

D is a gas

The melting point is 15 degrees celcius

Its boiling point is 110 degree celcius

A,C and D are the portions showing the change in state

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Answer : The value of equilibrium constant (K) is, $5.71\times 10^4$

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First we have to calculate the concentration of $N_2,O_2\text{ and }N_2O$

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and,

$\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{2.50\times 10^{-5}mol}{2.00L}=1.25\times 10^{-5}M$

and,

$\text{Concentration of }N_2O=\frac{\text{Moles of }N_2O}{\text{Volume of solution}}=\frac{2.00\times 10^{-2}mol}{2.00L}=1.00\times 10^{-2}M$

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

$N_2(g)+O_2(g)\rightarrow 2N_2O(g)$

The expression for equilibrium constant is:

$K=\frac{[N_2O]^2}{[N_2][O_2]}$

Now put all the given values in this expression, we get:

$K=\frac{(1.00\times 10^{-2})^2}{(1.4\times 10^{-4})\times (1.25\times 10^{-5})}$

$K=5.71\times 10^4$

Thus, the value of equilibrium constant (K) is, $5.71\times 10^4$

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4 years ago