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3 years ago

(c) 7 bananas and 5 mangoes cost $36. Write an equation in b and m to represent the information.

Mathematics

1 answer:

luda_lava [24]3 years ago

5 0

Answer:

7b+5m = 36

Step-by-step explanation:

7 bananas and 5 mangoes cost $36

7b+5m = 36

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How long will it take for an airplane that averages 95 miles an hour to fly 1,710 miles?

zysi [14]

The correct answer is 18 hope that helped♥

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3 years ago

A movie complex is showing the same movie and three theaters in theater and a 60 of the 80 seats are taken and theater B 42 seat

Anna [14]

Answer:

Theatre C.

Step-by-step explanation:

Theatre A:

60 of the 80 seats are taken.

% seats taken = seats taken/total seats * 100

= 60/80 * 100

= 75%

Theatre B:

Total seats = number of seats taken + number of empty seats

= 42 + 18

= 60

% seats taken = seats taken/total seats * 100

= 42/60 * 100

= 70%

Theatre C:

Total seats = number of seats taken + number of empty seats

90 = X + 18

X = 72

% seats taken = seats taken/total seats * 100

= 72/90 * 100

= 80%

Theatre C with 80% of seats taken.

4 0

4 years ago

Read 2 more answers

Perform the requested operation or operations. f(x) = x minus eight divided by seven.; g(x) = 7x + 8, find g(f(x)).

Anarel [89]

F(x)=(x-8)/7
<span>g(x) = 7x + 8
</span>g(f(x))-------------- > 7*((x-8)/7)+8----------- >x-8+8=x
the answer is x

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3 years ago

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Many people think that a national lobby's successful fight against gun control legislation is reflecting the will of a minority

Andre45 [30]

Answer:

The 95% confidence interval of the true proportion of all Americans who are in favor of gun control legislation is (0.5471, 0.5779).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

A random sample of 4000 citizens yielded 2250 who are in favor of gun control legislation. This means that $n = 4000$ and $\pi = \frac{2250}{4000} = 0.5625$

Estimate the true proportion of all Americans who are in favor of gun control legislation using a 95% confidence interval

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5625 - 1.96\sqrt{\frac{0.5625*0.4375}{4000}} = 0.5471$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5625 + 1.96\sqrt{\frac{0.5625*0.4375}{4000}} = 0.5779$

The 95% confidence interval of the true proportion of all Americans who are in favor of gun control legislation is (0.5471, 0.5779).

8 0

3 years ago

Slove for m m+7=3+m+4

ser-zykov [4K]

Answer:

no solution

Step-by-step explanation:

4 0

3 years ago

(c) 7 bananas and 5 mangoes cost $36. Write an equation in b and m to represent the information.​

(c) 7 bananas and 5 mangoes cost $36. Write an equation in b and m to represent the information.