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3 years ago

Which rational number is the greatest a. 0.55 b. 0.6 c. 9/20 d. 1/2

Mathematics

1 answer:

Charra [1.4K]3 years ago

6 0

I think d.1/2 number is the greatest rational number .

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A cylinder has a Height 12 and a radius 3.7 what is it’s volume?

Juli2301 [7.4K]

The formula for the volume of a cylinder is v = π r² h
Let's use 3.14 for π.
Square 3.7 to get 13.69.
Multiply that by 3.14.
v = 42.9866 x 12
Finally, multiply it by 12.
v = 515.8392

You could also express your answer in terms of pi.
Square 3.7 to get 13.69.
Multiply it by 12. 164.28 is what you get.
v = 164.28π

Hope this helps!

7 0

4 years ago

HHHHHHHELP MEEEEEEEEEEE

irga5000 [103]

Answer:

4th one is the right answer.

| x | -2 | 1 | 2 | 3 |

| y | -6 | 3| 6 | 9 |

Step-by-step explanation:

The x and y relationship is in the form y=kx and the graph starts from the origin.

Therefore the graph represents a proportional relationship which holds a equation y=x/3, where k=1/3.

5 0

3 years ago

Find (f+g)(x) if f(x)=3x+10x and g(x)=5x-3

otez555 [7]

3x-5x+3 Answer:

Step-by-step explanation:

7 0

4 years ago

PLEASE HELP! URGENT WILL GIVE BRAINLEST! PLEASE ANSWER ALL QUESTIONS!!! IF YOU DON'T I WILL REPORT.

Nesterboy [21]

Answer:

1. b) 135°, 225°

2. c) 0°, 180°

3. a) π/2

4. b) 30°, 150°, 210°, 330°

5. a) 1.25 radians and 4.39 radians

Step-by-step explanation:

Question 1

$\begin{aligned}\cos \theta & = -\dfrac{\sqrt{2}}{2}\\\implies \theta & = \cos^{-1}\left(-\dfrac{\sqrt{2}}{2}\right)\\\\& = 135^{\circ} \pm 360^{\circ}n, 225^{\circ} \pm 360^{\circ}\\\\& = 135^{\circ}, 225^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}$

Question 2

$\begin{aligned}\cos^2 \theta-1 & = 0\\\implies \cos^2 \theta & = 1\\\cos \theta & = \pm1\\\theta & = \cos^{-1}(\pm1)\\& = 0^{\circ} \pm 360^{\circ}n, 180^{\circ} \pm360^{\circ}n\\& = 0^{\circ}, 180^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}$

Question 3

$\begin{aligned}\sin \theta & = 1\\\implies \theta & = \sin^{-1}(1)\\\theta & = \dfrac{\pi}{2}\pm2\pi n\\\theta & = \dfrac{\pi}{2}\quad \textsf{for}\:0 \leq \theta < 2 \pi \end{aligned}$

Question 4

$\begin{aligned}3 \tan^2 \theta-1 & = 0\\\implies \tan^2 \theta & = \dfrac{1}{3}\\\tan \theta & = \pm\dfrac{1}{\sqrt{3}}\\\theta & = \tan^{-1}\left(\pm\dfrac{1}{\sqrt{3}}\right)\\& = 30^{\circ}\pm180^{\circ}n, 150^{\circ}\pm180^{\circ}n\\& = 30^{\circ}, 150^{\circ}, 210^{\circ}, 330^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}$

Question 5

$\begin{aligned}2 \tan \theta -6 & = 0\\\implies \tan \theta & = 3\\\theta & = \tan^{-1}(3)\\\theta & = 1.25\pm \pi n\\\theta & = 1.25, 4.39 \quad \textsf{for}\:0^{\circ}\leq \theta < 2 \pi \end{aligned}$

5 0

2 years ago

Read 2 more answers

Urgent help !!

aksik [14]

Answer:

its c

Step-by-step explanation:

i think im sorry if it wrong this a unusal term for operation

4 0

4 years ago