Answer:
Fog computing
Explanation:
Fog computing or fogging is an decentralized architecture that resides between the cloud and the data source. Fog brings the cloud closer to the data source, that is, it brings resource exploitation, security polices and operational cost closer to the data source.
In our scenario, with fogging in place, the generated sensor data will be preprocessed closer to the local site. The data will preprocessed faster and the quality of the processed data will be greatly increased.
Answer:
Following are the correct python code to this question:
n1 = float(input('Input first number: '))#input first number
n2 = float(input('Input second number: '))#input second number
n3 = float(input('Input third number: '))#input third number
n4 = float(input('Input fourth number: '))#input fourth number
average = (n1+n2+n3+n4)/4 #calculate input number average
product = n1*n2*n3*n4 # calculate input number product
print('product: {:.0f} average: {:.0f}'.format(round(product),round(average))) #print product and average using round function
print('product: {:.3f} average: {:.3f}'.format(product,average)) #print product and average value
Output:
Please find the attachment.
Explanation:
The description of the above python code can be defined as follows:
- In the above python program four variable "n1, n2, n3, and n4" is defined, in which we take input from the user end, and in these user inputs we use the float method, that converts all the input value in to float value.
- In the next step, two variable average and product are defined, that calculate all input numbers product, average, and hold value in its variable.
- In the last line, the print method is used, which prints its variable value by using a round and format method.
Answer:
Replace /* Your solution goes here */ with:
cin>>matchValue;
numMatches = 0;
for (i = 0; i < userValues.size(); ++i) {
if(matchValue == userValues.at(i))
{
numMatches++;
}
}
Explanation:
This line gets input for matchValue
<em>cin>>matchValue;
</em>
This line initializes numMatches to 0
<em>numMatches = 0;
</em>
The following iteration checks for the number of matches (numMatches) of the matchValue
<em>for (i = 0; i < userValues.size(); ++i) {
</em>
<em>if(matchValue == userValues.at(i))
</em>
<em>{
</em>
<em> numMatches++;
</em>
<em>}
</em>
<em>}
</em>
<em>See Attachment for full source code</em>
Answer:
12. for (i = 0 ; i < testGrades.length ; i+=1 ){
13. if (testGrades[i] > 100){
14. sumExtra = sumExtra + testGrades[i] - 100;}
15. }
Explanation:
We first iterate through the entire testGrades array. For each test score that is in testGrades ( that is testGrades[i] ), we see whether or not the test grade is above 100 (See line 12) . If test grade is greater than 100, this means we have extra credit. We simply subtract 100 from the test grade, add it with the previous value of sumExtra and store the value back in sumExtra(see line 14). Once i is greater than the length of the test grades, the loop is exited. We can now print sumExtra to obtain the result.
Answer:
the answer is going to be printer
