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2 years ago

8

What would this one be?

1 answer:

tester [92]2 years ago

8 0

Answer:

I believe it's 6/10

Step-by-step explanation:

3/5 times 2 = 6/10

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For a field trip 20 students rode in cars and the rest filled 5 busses. How many students were in each bus if 210 students were

xeze [42]

First do 210 - 20 = 190
Then do 190/5 = 38
38 people per bus is the answer!!!!

3 0

3 years ago

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A number increased by 8 gives the same result as a number multiplied by 8. whay is that number?

Airida [17]

$x+8=8x\\
7x=8\\
x=\frac{8}{7}$

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2 years ago

Which of the following correctly shows the re-grouping for 45 x 12? Group of answer choices 40 x 10; 5 x 10; 40 x 2; 5 x 40

Damm [24]

Answer:

40x10;5x10;40x2;5x2

400+50+80+10

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5 0

2 years ago

Please round 0.02623 to the nearest hundred.<br> ||||<br> Thank you guys! please answer soon!

ElenaW [278]

Answer:

0.03

Step-by-step explanation:

6 is greater then 5, so you add 1 to 2 making 0.03

5 0

3 years ago

Read 2 more answers

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

2 years ago