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Volgvan
3 years ago
6

When this 3-digit number is rounded to the nearest ten, the sum of its digits is 16. The hundreds digit of this number is 8 and

the ones digit is 5. What is the number?​
Mathematics
2 answers:
kramer3 years ago
6 0

Answer:

835

Step-by-step explanation:

We know that the hundreds is 8 and the ones is 5 so the sum needed is 16-(8+5), which equals 3 :)

TEA [102]3 years ago
3 0
835 is your answer…….
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Hich of the following are the coordinates of the vertex of y = x2 − 10x + 2?
ANEK [815]
The vertex is in essence the turning point of the parabola y = x²<span> − 10x + 2

the x coordinate of the turning point = </span>- \frac{b}{2a}
                                                         = - \frac{-(10)}{2(1)}
                                                         =  5

when x = 5, y = (5)² - 10(5) + 2
                      = -23

Thus coordinate or vertex is ( 5, -23)

6 0
2 years ago
The mean life of a television set is 119119 months with a standard deviation of 1414 months. If a sample of 7474 televisions is
Pepsi [2]

Answer:

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.6275

What is the probability that the sample mean would differ from the true mean by less than 1.11 months?

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.6275}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.6275}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

3 0
3 years ago
Another i-ready question! Sorry i am clueless and need a 100% Please help!
Delicious77 [7]

Answer:

3rd

Step-by-step explanation:

4 0
2 years ago
Which pair of lines are parallel? Need to show work
zaharov [31]

Answer:

E

Step-by-step explanation:

7 0
2 years ago
I'll mark as Brainliest, Please answer ASAP, Ihave MCAS tomorrow. How could this be true?? Please Explain.​
Vaselesa [24]

Answer:

See below

Step-by-step explanation:

The number of loaves of bread remaining can only go as low as ZERO (you can't have negative loaves) ...and can only go as high as when h = 0

     so    0 = 42-3.5 h    

             3.5 h = 42

                h = 12       and   min is  h = 0   ( when there are 42 loaves to start)

So:

<u>0≤ h ≤ 12 </u>

5 0
2 years ago
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