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RideAnS [48]
2 years ago
8

a university department administers a survey regardring student satisfaction based on the survey results the department provides

a confidence interval estimate of 60% to 80% for student satisfaction if the department wishes to construct a confidence interval the more accurate represents the proportion of a student satisfaction how should the design be altered
Mathematics
1 answer:
dlinn [17]2 years ago
6 0

Answer:

Change the confidence interval.

Step-by-step explanation:

The confidence interval should be altered . If a 95 % or 90% confidence interval is set then better results can be obtained for student satisfaction.

A 90 or 95  or 99 percent confidence interval will show  a greater range of the data that lies within or without the given criteria.

95 % confidence interval does not mean that the probability is 95% . It means that we are 95% of the data lies  or does not lie within the specific range.

This gives better results as compared to 60- 80 % confidence intervals.

If 95% of the students are satisfied as compared to 60% or 80% , this shows more accuracy.

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Answer:

a_{n}= 1+2n and 63

Step-by-step explanation:

the question belongs to arithmetic sequence and a_{n} can be determined by the formula

a_{n}= a1 + d (n-1)

Let " a_{n} " represents the number of band members in the nth row

and 'd' represents the common difference.( as stated each row  has 2 more band members than the row before it)

therefore, d=2

'a1' represents first row that has three members. So, a1 = 3

->Rule for nth term will be:

a_{n}= 3 + 2(n-1)

a_{n}= 3 + 2n -2

a_{n}= 1+2n

-> In order to find total number of band members 'S_{7}'

Let S_{n} represent total number in n rows

We'll use the formula, i.e  S_{n} = n/1 (a_{1} +  a_{n})

where, n is the number of terms, a_{1} is the first term and a_{n} is the last term

So,

n=7

a_{7} = 1 + 2(7)= 15

=>S_{7} = 7/2 (3 + 15)

S_{7} = 63

The total number of band members are 63

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