Which graph summarize a set of data using an interval scale?

Question 14 (1 point)

valina [46]

Answer:

C(x) = 25 + 2x

Step-by-step explanation:

He already has 25 cards.

He is collecting 2 cards per month. In x months, he will have collected:

2 * x = 2x cards

That means that the number of cards he will have after x months will be the sum of the cards he already has and the cards he collects per month:

C(x) = 25 + 2x

8 0

3 years ago

Write an inequality for the graph

natima [27]

The open circle means the inequality will be greater than or equal to (≥) or less than or equal to (≤).
A closed circle means the inequality will be greater than (>) or less than (<)

An arrow pointing right to increasingly positive values means the inequality is getting greater (> or ≥)
A narrowing pointing left to increasingly negative values means the inequality is getting lesser (< or ≤)

So for this graph with an open circle and rightward pointing arrow, “x” will be some number on the number line greater than the first point of -38:
x > -38

6 0

3 years ago

What is the arc length of an arc with radius 10 in and central angle 60 degrees ? Show your work.

emmasim [6.3K]

Answer:

$\huge \boxed{ \boxed{ \red{{s \approx \: 10.47}}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

geometry
PEMDAS

<h3>tips and formulas:</h3>

$s = \frac{\pi {r} \theta}{180}$

<h3>given:</h3>

r=10
$\theta = 60$

<h3>let's solve:</h3>

$\sf sustitute \: the \: value s \: of \: \theta \: and \: r : \\ =\frac{\pi \times 10 \times 60}{180}$
$\sf rediuce \: 60 : \\ =\frac{\pi \times 10 \times \cancel{60} \: ^{1} }{ \cancel{180} \: \:^{3} } \\ =\frac{\pi \times 10}{3}$
$\sf use \: 3.14 \: for \: \pi : \\ = \frac{3.14 \times 10}{3}$
$\sf simplify \: multipication : \\ = \frac{31.4}{3} \\ \approx \: 10.47$

5 0

3 years ago

How do i calculate percent accuracy? I got 20 questions out of 21 correct but I need to figure out the percent accuracy for anot

Mandarinka [93]

You need to do 20 divide by 21 to get a decimal. Then if you multiply the decimal by hundred you should get the percentage.

7 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, <u><em>the test statistics</em></u> = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago