Answer:
yes darling? why? can help you
Step-by-step explanation:
Answer: AAA similarity.
Step-by-step explanation: CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have
∠CED ≅ ∠CBA,
∠CDE ≅ ∠CAB
and
∠DCE ≅ ∠ACB [same angle]
Hence, by AAA (angle-angle-angle) similarity,
△CED ~ △ABC.
Thus, the correct option is AAA similarity.
Answer:
Step-by-step explanation:
The equation Thomas wrote is:
...equation 1
Let us subtract 3x from both sides to get:
We now multiply through by 2 to get:
....equation 2
We can see that equation one and two are equivalent and hence have the same solution.
Therefore Sandra's equation is 