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Illusion [34]
2 years ago
10

9) A heptagon has 6 exterior angles with measures of 47, 55, 62, 64, 54, and 49. What is the measure of the interior angle adjac

ent to the seventh exterior angle?
Mathematics
1 answer:
svetlana [45]2 years ago
6 0

Answer:

seventh  interior angle=∠x=29°

Step-by-step explanation:

sum of interior angle of polygon is equal to 360°

let seventh angle of heptagon is x

∠x+47°+55°+62°+64°+54°+49°=360°

∠x=360°-(47°+55°+62°+64°+54°+49°)

∠x=360°-331°=29°

∠x=29°

seventh  interior angle=∠x=29° answer

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The answer is 1400

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Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours
s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

cos(x) = \frac{adjacent}{hypotenuse}

cos(47) = \frac{22miles}{hypotenuse} .... flip both fractions.

\frac{1}{cos(47)} = \frac{hypotenuse}{22miles} .... multiply both sides by 22

\frac{22mi}{cos(47)} = hypotenuse

32.26mi = hypotenuse = B

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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3 years ago
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Step-by-step explanation:

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In a study of 420,095 Danish cell phone users, 135 subjects developed cancer of the brain or nervous system (based on data from
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Answer:

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.

Step-by-step explanation:

1) Data given and notation  

n=420095 represent the random sample taken

X=135 represent the subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

\hat p=\frac{135}{420095}=0.0003214 estimated proportion of subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

p_o=0.00034 is the value that we want to test

\alpha=0.005 represent the significance level

Confidence=99.5% or 0.995

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the brain or nervous system at a rate that is different from the rate of 0.0340% :  

Null hypothesis:p=0.00034  

Alternative hypothesis:p \neq 0.00034  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.005. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.  

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21 first-graders and 54 other students attended a school assembly. What percentage of the students at the assembly were first-gr
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21+ 54= 76

21/76= 27.6%

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