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spayn [35]
3 years ago
10

Ive been having this question for a while "what do you use first PEMDAS or Order of Operations". Well you might say it doesn't m

atter because a problem like this 5(3+8)=x if you use PEMDAS u first add the eight and the three and you would get eleven then you times the eleven with the five to get fifty five. So x=55. If you use Order of Operations you would multiply the three and eight by five to get 15+40=x you would add the fifteen and the forty to get fifty five making x=55. But if you took the problem {3(525/4π)}^1/3=R
then its a different situation heres the problem solved with PEMDAS.


{3(525/4π)}^1/3

{3(525/12.57)}^1/3

{3•41.77}^1/3

125.30^1/3=4.90

R=4.90


Now this is a step by step explanation on how to do order of operations.

{3(525/4π)}^1/3

(1575/12•9.40)^1/3

(1575/112.80)^1/3

13.90^1/3=2.30

R=2.30


So as you see these two equations have different answers. Now agin which of the two of them do i use Order of Operations or PEMDAS.


Please give a step by step explanation why i should use either or. All these problems were rounded to the nearest hundredth.
Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

Order of Operations was aught at a younger age for those just grasping the idea of multiplication and division. Exposing PEMDAS at a young age would confuse them too much, hence the order of operation groups, addition/subtraction and multiplication/division. So for the second example problem, PEMDAS would be correct because it does involve you to use parentheses as well as exponents to solve for. Very easy to mix up between order of operations and PEMDAS, but just look at it as if Order of operations is a beginner level of PEMDAS.

Step-by-step explanation:

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Step-by-step explanation:

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f(x) = \frac{1}{x-2} + 1

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3 years ago
Reese is selling lemonade at the parade. He gets to keep 50% of the money he collects. A large lemonade is $6.00 and a small lem
yuradex [85]

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Step-by-step explanation:

Given data

We are given that

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Ques 8:

The Volume(V) in cubic feet of an aquarium id modeled by the polynomial function V(x)= x^{3}+2x^{2}-13x+10

a) We have to explain that why x =4 is not a possible rational zero.

By Factor theorem, which states that a polynomial f(x) has a factor (x - k) if and only if f(k)=0.

For this , we will substitute the value of x in the given function.

V(x)=x^{3}+2x^{2}-13x+10

V(4)=4^{3}+2(4)^{2}-13(4)+10

V(4)=4^{3}+2(4)^{2}-13(4)+10

V(4)=54 which is not equal to zero.

Therefore, x=4 is not a possible rational zero.

(b) To show that (x-1) is a factor of V(x).

By Factor theorem, which states that a polynomial f(x) has a factor (x - k) if and only if f(k)=0.

Let (x-1)=0

So, x=1.

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Therefore, (x-1) is a factor of V(x).

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Dividing the given function by (x-1).

On dividing, we get quotient as x^{2}+3x-10

So, factored form is = (x-1)(x^{2}+3x-10)

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Answer:

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Step-by-step explanation:

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