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Flura [38]
3 years ago
11

PLSSS HELP HERES IMAGEEE

Mathematics
2 answers:
frozen [14]3 years ago
8 0

\text{(H, A and S), (Y, D and T) and (H, D and S)}

adelina 88 [10]3 years ago
7 0
3 is correct answer!!
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-2.925 as a mixed number
grin007 [14]

Answer: -2 37/40

You convert it to a mixed number by placing the numbers to the right of the decimal over 1000. Then reduce the fraction.

4 0
3 years ago
Which theorem explains why the circumcenter is equidistance
ioda
Perpendicular Bisector Theorem
8 0
3 years ago
Can someone help me on the LCM numbers plzzz
BabaBlast [244]

The least common multiple, or LCM, is another number that's useful in solving many math problems. Let's find the LCM of 30 and 45. One way to find the least common multiple of two numbers is to first list the prime factors of each number.

30 = 2 × 3 × 5
45 = 3 × 3 × 5

Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

2: one occurrence
3: two occurrences
5: one occurrence
2 × 3 × 3 × 5 = 90 <— LCM

After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers.

4 0
4 years ago
The radius of a frisbee is 5 inches. What is the circumference of the frisbee in terms of (pi)?
vaieri [72.5K]

Answer:

10π inches

Step-by-step explanation:

C = 2πr

C = 2π(5)

C = 10π ≈ 31.42

4 0
3 years ago
In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 15 boys an
denis-greek [22]

Answer:

There are a total of possible 1820 results.

Step-by-step explanation:

Since there are two competitions, one for boys and one for girls, and we want all the possible results we will calculate the possible combinations for the boys and multiply them by the possible combinations for the girls. This is shown below:

Boys = \frac{15!}{3!(15 - 3)!} = \frac{15!}{3!12!} = \frac{15*14*13*12!}{3!12!}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = 455

Girls = \frac{4!}{3!*(4 - 3)!}\\Girls = \frac{4*3!}{3!}\\Girls = 4

Total number of possible results:

results = 4*455\\results = 1820

3 0
4 years ago
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