Question

Again with math, can someone help?​

Answer 1

Answer:

Answer: F. 5

${ \tt{ \frac{ {7}^{x} - \sqrt[3]{y} }{2z} }} \\ \\ = { \tt{ \frac{ {7}^{2} - \sqrt[3]{729} }{(2 \times 4)} }} \\ \\ = { \tt{ \frac{40}{8} }} \\ \\ = { \tt{5}}$

Answer 2

Answer:

F. 5

Step-by-step explanation:

7^2 - 3√729 / 2(4)

=49-9/ 8

=40/8

=5