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Marrrta [24]
3 years ago
8

How many molecules are in 3.6 grams of NaCl? Question options:

Chemistry
1 answer:
Levart [38]3 years ago
5 0

Answer:

\boxed {\boxed {\sf 3.7 * 10^{22} \ molecules \ NaCl}}

Explanation:

We are asked to find how many molecules are in 3.6 grams of sodium chloride.

<h3>1. Convert Grams to Moles </h3>

First, we convert grams to moles using the molar mass. These values are equivalent to atomic masses on the Periodic Table, but the units are grams per moles instead of atomic mass units. Look up the molar masses of the individual elements: sodium and chlorine.

  • Na: 22.9897693 g/mol
  • Cl: 35.45 g/mol

There are no subscripts in the chemical formula (NaCl), so we simply add the 2 molar masses.

  • NaCl: 22.9897693 + 35.45 = 58.4397693 g/mol

Now we will convert using dimensional analysis. First, set up a ratio using the molar mass.

\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}

We are converting 3.6 grams to moles, so we must multiply the ratio by this value.

3.6 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}

Flip the ratio so the units of grams of sodium chloride cancel.

3.6 \ g \ NaCl *\frac { 1 \ mol \ NaCl}{58.4397693 \ g \ NaCl}

3.6  *\frac { 1 \ mol \ NaCl}{58.4397693}

\frac { 3.6}{58.4397693} \ mol \ NaCl

0.06160188589 \ mol \ NaCl

<h3>2. Convert Moles to Molecules </h3>

Next, we convert moles to molecules using Avogadro's Number. This is 6.022 × 10²³ and it tells us the number of particles (atoms, molecules, formula units, etc). In this case, the particles are molecules of sodium chloride. Let's set up another ratio.

\frac {6.022 \times 10^{23} \ molecules \ NaCl}{ 1 \ mol \ NaCl}

Multiply by the number of moles we calculated.

0.06160188589 \ mol \ NaCl * \frac{6.022 \times 10^{23} \ molecules \ NaCl}{1 \ mol \ NaCl}

The units of moles of sodium chloride cancel.

0.06160188589 * \frac{6.022 \times 10^{23} \ molecules \ NaCl}{1 }

3.70966557*10^{22} \ molecules \ NaCl

<h3>3. Round </h3>

The original measurement of grams (3.6) has 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 0 in the hundredth place tells us to leave the 7 in the tenth place.

3.7 * 10^{22} \ molecules \ NaCl

There are 3.7 * 10^{22} \ molecules \ NaCl in 3.6 grams and the correct answer is choice D.

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g If 0.600 g of a gas occupies 211 mL at 24 oC and 660 mmHg of pressure, what is the molar mass of the gas
Alisiya [41]

Answer:

79.89 g/mol

Explanation:

The following data were obtained from the question:

Mass (m) of gas = 0.6 g

Volume (V) = 211 mL

Temperature (T) = 24 °C

Pressure (P) = 660 mmHg

Molar mass of gas =.?

Next, we convert 24 °C to Kelvin temperature. This can be obtained as follow:

Temperature (K) = temperature (°C) + 273

Temperature (°C ) = 24 °C

Temperature (K) = 24 + 273 = 297 K

Next, we shall convert 211 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

211 mL = 211 mL × 1 L / 1000 mL

211 mL = 0.211 L

Next, we shall convert 660 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

660 mmHg = 660 mmHg × 1 atm / 760 mmHg

660 mmHg = 0.868 atm

Next, we shall determine the number of mole of the gas. This can be obtained as shown below:

Volume (V) = 0.211 L

Temperature (T) = 297 K

Pressure (P) = 0.868 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

PV = nRT

0.868 × 0.211 = n × 0.0821 × 297

Divide both side by 0.0821 × 297

n = (0.868 × 0.211) / (0.0821 × 297)

n = 7.51×10¯³ mole.

Finally, we shall determine the molar mass of the gas as shown below:

Mass of gas = 0.6 g

Number of mole of gas = 7.51×10¯³ mole.

Molar mass of gas =.?

Mole = mass /Molar mass

7.51×10¯³ = 0.6 / Molar mass

Cross multiply

7.51×10¯³ × molar mass = 0.6

Divide both side by 7.51×10¯³

Molar mass = 0.6 / 7.51×10¯³

Molar mass of gas = 79.89 g/mol

3 0
3 years ago
If 5.0 grams of sucrose, C12H22O11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting soluti
GaryK [48]

Answer : The boiling point of the resulting solution is, 100.6^oC

Explanation :

Formula used for Elevation in boiling point :

\Delta T_b=i\times k_b\times m

or,

T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of water = 100^oC

k_b = boiling point constant  = 0.52^oC/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute (sucrose) = 5.0 g

w_1 = mass of solvent (water) = 10.0 g

M_2 = molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

(T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}

T_b=100.6^oC

Therefore, the boiling point of the resulting solution is, 100.6^oC

5 0
3 years ago
A force of 25 newtons is exerted over an area of 50 square meters. Calculate
snow_lady [41]

Answer:

the pressure exerted in pascals is 0.5 Pa

Explanation:

The computation of the pressure exerted in pascals is shown below:

As we know that

Pressure = force ÷ area

= 25 ÷ 50

= 0.5 Pa

Hence, the pressure exerted in pascals is 0.5 Pa

We simply applied the above formula so that the correct pressure could come

4 0
3 years ago
Why bonding of water molecule called a pure <br>​
Vesna [10]

Answer:

A molecule of water has two hydrogen atoms. Both of these atoms can form a hydrogen bond with oxygen atoms of different water molecules. Every water molecule can be hydrogen bonded with up to three other water molecules

4 0
2 years ago
A solution is to be prepared with a sodium ion concentrationof
Lina20 [59]

Answer : The mass of sodium sulfate needed is 5.7085 grams.

Explanation : Given,

Concentration of sodium ion = 0.148 mol/L

Volume of solution = 2.29 L

Molar mass of sodium sulfate = 142 g/mole

First we have to determine the moles of sodium ion.

\text{Concentration of sodium ion}=\frac{\text{Moles of sodium ion}}{\text{Volume of solution}}

0.184mol/L=\frac{\text{Moles of sodium ion}}{2.29L}

\text{Moles of sodium ion}=0.08035mole

Now we have to calculate the moles of sodium sulfate.

The balanced chemical reaction will be,

Na_2SO_4\rightarrow 2Na^++SO_4^{2-}

As, 2 moles of sodium ion produced from 1 moles of Na_2SO_4

So, 0.08035 moles of sodium ion produced from \frac{0.08035}{2}=0.040175 moles of Na_2SO_4

Now we have to calculate the mass of sodium sulfate.

\text{Mass of }Na_2SO_4=\text{Moles of }Na_2SO_4\times \text{Molar mass of }Na_2SO_4

\text{Mass of }Na_2SO_4=0.040175mole\times 142g/mole=5.7085g

Therefore, the mass of sodium sulfate needed is 5.7085 grams.

3 0
4 years ago
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