5. पहले अठारह तत्वों के विभिन्न कक्षों में इलेक्ट्रॉन वितरण के नियम कोलिखिए।
1 answer:
You might be interested in
Answer: 3.0 moles of water are needed to react with a mole of 3.0 of Na
Explanation:
The balanced chemical reaction of sodium with water is as follows:
According to stoichiometry:
2 moles of sodium reacts with = 2 moles of water
Thus 3.0 moles of sodium reacts with =
moles of water
3.0 moles of water are needed to react with a mole of 3.0 of Na
Answer:
68.3 kilo Pascal is the pressure in the container.
Explanation:
To calculate the new pressure , we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.
The equation given by this law is:
where,
are initial pressure and volume.
are final pressure and volume.
We are given:
Putting values in above equation, we get:
68.3 kilo Pascal is the pressure in the container.
Grams of Chromium(III) nitrate produced : 268.95 g
<h3>Further explanation</h3>Given
0.85 moles of Lead(IV) nitrate
Required
grams of Chromium(III) nitrate
Solution
Reaction
Balanced equation :
<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>
From the equation, mol ratio of Pb(NO₃)₄ : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃
mol Cr(NO₃)₃ =
Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :
mass = mol x MW
mass = 1.13 x 238.0108
mass = 268.95 g