Last question plz make sure it’s right and NO WEBSITES/LINKS will mark brainiest if right :)
1 answer:
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Answer:
1) he prior probability of the bid being successful (that is, prior to the request for additional information = 0.5
2) the conditional probability of a request for additional information given that the bid will ultimately be successful = 0.74
3) the posterior probability that the bid will be successful given a request for additional information = 0.65
Step-by-step explanation:
The concept of probability of success and failure was used as well the approach of bayes formular or posterior probability. Keeping in mind that P(Success) + P(Failure) = 1
The detailed steps is as shown in the attachment.
The ball will be fastest right before it hits the ground because of gravity.
First, let's find the value of t where the ball hits the ground.
-8t²+25 = 0
-8t² = -25
t² =
t =
Note: t has to be positive, which is why there is no positive/negative symbol.
Now, let's calculate the derivative of this function. The derivative will give us the speed of the ball for time t.
d/dx = -16t
Now, let's plug in the value of t
-16 ( }
=
=
Take the absolute value of that because speed can't be negative
That's the speed of the ball. You can convert that into decimal if you'd like.
Have an awesome day! :)
First, let's find the value of t where the ball hits the ground.
-8t²+25 = 0
-8t² = -25
t² =
t =
Note: t has to be positive, which is why there is no positive/negative symbol.
Now, let's calculate the derivative of this function. The derivative will give us the speed of the ball for time t.
d/dx = -16t
Now, let's plug in the value of t
-16 (
=
=
Take the absolute value of that because speed can't be negative
That's the speed of the ball. You can convert that into decimal if you'd like.
Have an awesome day! :)