let h = horse, let c = cow, let p = pig
so,
hcp
hpc
cph
chp
phc
pch
so, that is 6 different ways she can arrange it.
first：76 ÷ 19/25=100
a:80 / 20 * 1 / 25 =0.16
b:80 * 5/4 =100
c:80 / 5 ÷ 1 / 4 =64
d:80 * 5/4 =100
e:80 * 4/5 =64
So I think both B and D should be the right answer
10=a/2 + 7
First subtract 7 from both sides
3=a/2
Next multiple 2 on both sides, so that a is by itself
3(2)=a
A=6
