angle AOB = 132 and is also the sum of angles AOD and
DOB. Hence
angle AOD + angle DOB = 132° ---> 1
angle COD = 141 and is also the sum of angles COB and BOD. Hence
angle COB + angle DOB = 141° ---> 2
Now we add the left sides together and the right sides of equations 1 and 2
together to form a new equation.
angle AOD + angle DOB + angle COB + angle DOB = 132 + 141 ---> 3
We should also note that:
angle AOD + angle DOB + angle COB = 180°
Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180
and solving for angle DOB:
180 + angle DOB = 132 + 141
angle DOB = 273 - 180 = 93°
Answer:
(a) 17°
(b) 78°
Step-by-step explanation:
(a) sin A= 0.2896
to calculate for "A" check for sin inverse of 0.2896
A= sin^-1(0.2896) = 16.83
to the nearest degree A= 17°
(b) tan A = 4.7046
A= tan^-1(4.7046)
A = 77.99
to the nearest degree A = 78°
6n^2-18n
1.find your GCF
"6n"
final answer;
6n(n-3)
False. It’s a quadrilateral.
The answer is 1.
Rise over run :)
