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serg [7]
2 years ago
7

HELP HELP! I NEED URGENT HELP WITH THIS equashin.

Mathematics
2 answers:
Leona [35]2 years ago
6 0

Answer:

V = 1071.79 yd^3

Step-by-step explanation:

The volume of a cone is

V = 1/3 pi r^2 h  where r is the radius and h is the height

We are given a diameter of 16 so the radius is 1/2 of the diameter or 8

The height is 16

V = 1/3 ( 3.14) (8)^2 ( 16)

V = 1071.78666 yd^3

Rounding to the nearest hundredth

V = 1071.79 yd^3

shutvik [7]2 years ago
4 0

\large\begin{gathered} {\underline{\boxed{ \rm {\red{Volume  \:  of    \: Cone \:  =  \: \pi \:  {r}^{2}  \:  \frac{h}{3} }}}}}\end{gathered}

\bf{\red{  \longrightarrow}} \tt \:   r \:  =  \:  \frac{Diameter}{2}  \\

\bf{\red{  \longrightarrow}} \tt \:   r \:  =  \:  \frac{16 \: yd}{2}  \\

\bf{\red{  \longrightarrow}} \tt \:   r \:  =  \:  \frac{ \cancel{16 \: yd} \:   \: ^{8} }{ \cancel{2}}  \\

\bf{\red{  \longrightarrow}} \tt \:   \large{\bf{{{\color{navy}{r \:  =  \:  8 \: yd}}}}}

\bf{\red{  \longrightarrow}} \tt  \:  \: \large{\bf{{{\color{navy}{h \:  =  \:  16 \: yd}}}}}

\bf \large \longrightarrow \:  \: 3.14 \:  \times  \: {8}^{2}  \:   \times  \:  \frac{16}{3}  \\

\bf \large \longrightarrow \:  \:3.14 \:  \times  \: 64 \:  \times  \:  \frac{16}{3}  \\

\bf \large \longrightarrow \:  \:3.14 \:  \times  \: 64 \:  \times  \:  \frac{ \cancel{16} \:   \: ^{5.33} }{ \cancel{3}}  \\

\bf \large \longrightarrow \:  \:3.14 \:  \times  \: 64 \:  \times  \: 5.33

\bf \large \longrightarrow \:  \:200.96 \:  \times  \: 5.3

\bf \large \longrightarrow \:  \:1071.79

Option (A) is the correct answer

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Answer:

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Step-by-step explanation:

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3 years ago
Con
mr Goodwill [35]

Answer:

The coordinates of E are E(x,y) = \left(\frac{9}{2}, 0 \right).

Step-by-step explanation:

The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.

Vectorially speaking, dilation is defined by the following operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y) - O(x,y)] (1)

Where:

O(x,y) - Point of reference.

P(x,y) - Original point.

P'(x,y) - Dilated point.

k - Dilation factor.

By applying this operation, point B becomes point D:

B(x,y) = (0,4), D(x,y) = (0,6)

D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]

D(x,y) = (0,0) + k\cdot (0,4)

(0,6) = (0,0) +(0,4\cdot k)

(0, 6) = (0,4\cdot k)

k = \frac{3}{2}

Lastly, we transform point C into point E by applying the same operation: C(x,y) = (3, 0), O(x,y) = (0,0) and k = \frac{3}{2}

E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]

E(x,y) = \left(\frac{9}{2}, 0 \right)

The coordinates of E are E(x,y) = \left(\frac{9}{2}, 0 \right).

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