2 years ago

Classify ∠2 and ∠6. Compare angle measures, and give the postulate or theorem that justifies it.

Mathematics

1 answer:

LenaWriter [7]2 years ago

4 0

Answer:

Explanation

Step-by-step explanation:

Angles 2 and 6 are corresponding angles in a transversal meaning they have the same measure.

You might be interested in

What is 0.49,0.5 and 1/5 from least to greatest?

brilliants [131]

1/5 (0.2)
0.49
0.5

Hope this helped!! xx

7 0

3 years ago

Students were surveyed about their favorite colors. 1/4 of the students preffered red, 1/8 of the students preffed blue, and 3/5

lapo4ka [179]

27 is how much kids did the survey because I added all the fractions together like how the question did 3/5 which is 3 × 5 = 15

8 0

3 years ago

Find the point of intersection<br> y=-3x-3<br> y=-3

Alla [95]

The answer would be -3

5 0

2 years ago

If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.

Pie

Given that $f^{(n)}(0)=(n+1)!$ , we have for $f(x)$ the Taylor series expansion about 0 as

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n$

Replace $n+1$ with $n$ , so that the series is equivalent to

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}$

and notice that

$\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}$

Recall that for $|x|$ , we have

$\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}$

which means

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}$
$\implies f(x)=\dfrac1{(1-x)^2}$

5 0

3 years ago

What is the domain of this table X 1 2 3 4 Y 2 4 3 2

Hoochie [10]

1,2,3,4 are the domain. The x column is always the domain.

3 0

3 years ago