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Troyanec [42]
3 years ago
6

Ivan has a sticker collection. 2/5 of his stickers are scratch-and-sniff stickers. 1/4 of his scratch-and-sniff stickers smell l

ike bananas. What fraction of Ivan's sticker collection smells like bananas? *
Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0

Answer:

1 / 10

Step-by-step explanation:

From the question :

Fraction of scratch and sniff sticker from total stickers = 2/5

1/4 of scratch and sniff stickers smell like banana :

Fraction of total stickers that smell like banana :

(Fraction of scratch and sniff sticker from total stickers) * (scratch and sniff stickers smell like banana)

= (2/5) * (1/4)

= 2 /20

= 1/10

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In April 2008, an audio CD was available for $14.01. the list price (full price) of the CD was $19.32. What was the percent disc
8_murik_8 [283]
19.30 - ( p / 100 )*19.32 = 14.01 ;
19.30( 1 - p/100 ) = 14.01 ;
1 - p/100 = 14.01 / 19.30
1 - p / 100 = 0.72 ;
p/100 = 1 - 72 / 100 ;
p/100 = 28 / 100 ;
p = 28 ;
The percent discount is 28% ;
4 0
3 years ago
Help asaaaaap please
katovenus [111]

Answer:

A. 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-5x - 1 ≤ -9

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 1 to both sides:                    -5x ≤ -8
  2. Divide -5 on both sides:             x ≥ 8/5

Here we see that any value <em>x</em> greater than or equal to 1.6 would work as a solution.

Therefore, our answer is A. 1, as it doesn't work as a solution.

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3 years ago
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Answer:

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Step-by-step explanation:

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Two real solutions of tx^2+3x_7=0
Olegator [25]

The number of solutions of a quadratic equation

ax^2+bx+c=0

Depends on its discriminant

/Delta=b^2-4ac

If /Delta>0 there are two distinct solutions

If /Delta=0 there are two coincident solutions

If /Delta<0 there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

The number of solutions of a quadratic equation

Depends on its discriminant

If there are two distinct solutions

If there are two coincident solutions

If there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]

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(f-g)(x) = (x^2 + 6x+9)-(x^2-9) =6x+18=6(x+3), which is the first second expression

(fxg)(x) = (x^2+6x+9)(x^2-9) = (x^4-9x^2)+(6x^3-54x)+(9x^2-81)=x^4+6x^3-54x-81, which is the fourth expression

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