Answer:
The concentration of HCl in the mixture is 1L of 50% HCl
Step-by-step explanation:
Here, we want to know the percentage of HCl present which refers to the its concentration.
Firstly, the total volume we have is 0.375 + 0.625 = 1 L
we can calculate the percentage as follows;
The percentage of the 25% present is 37.5%
while the percentage of the 75% present is 62.5%
When we say the percentage present, we are referring to the amounts of the total liters which is 1 present.
So the concentration of the final mixture will be;
(37.5% of 25) + (62.5% of 65)
= 9.375% + 40.625%
Adding both gives = 50%
So the concentration we have is 1L of 50% HCl
B!!!!!!!!!!!!!!!!!!!!!!!!!!!
6. is divide 17.5 by 0.5 then multiply by $0.75
(17.5<span>÷0.5)*0.75=$26.25
This is the order in which you should do the equation |
|
1 P Parenthasis ()
2 E Exponents </span><span> </span><span>
3 M Multiply
4 D Divide
5 A Add
6 S Subtract
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Odd numbers are being added and being added by a greater number