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Ksivusya [100]
2 years ago
12

Need help with solving please

Mathematics
1 answer:
attashe74 [19]2 years ago
5 0

Answer:

x=8

Step-by-step explanation:

4 ^(1/2x) = 256

Rewriting 256 as a power of 4

4 ^(1/2x) = 4^4

Since the bases are the same, the exponents are the same

1/2x = 4

Multiply each side by 2

1/2x *2 = 4*2

x=8

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baherus [9]

Answer:

i not good at this but i think 2 6 18 54 could be the answer if not im so sorry

Step-by-step explanation:

5 0
2 years ago
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||<br> o34<br> 38<br> o33<br> оз10<br> Y’all what this is ?
Effectus [21]

Answer:

i think its the 3rd one im sorry if im wrong

Step-by-step explanation:

4 0
2 years ago
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
3 years ago
Which of the following must be true in order for SAND to be in a rhombus? Select all that apply
Ahat [919]

Answer:

Consecutive sides must be congruent.

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Step-by-step explanation:

Rhombus:

1. Sides: all 4 sides are congruent.

Then consecutive sides must be congruent.

2.Diagonals : Diagonals bisect each other at 90°.

So, second option is wrong.

3. Sum of interior angle is 360°.

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3 years ago
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exis [7]

Answer:

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Step-by-step explanation:

we know that

The domain of x is equal to the interval--------> (-2,3]

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All real numbers greater than -2 and less than or equal to 3

Let

y=5x+1

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For x>-2

y >5(-2)+1\\y > -9

so

The range of the function is the interval--------> (-9,16]

5 0
3 years ago
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