1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kotegsom [21]
3 years ago
8

HELP QUICK!!!

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0
The answer is the height of 17 and base is 12 of this helps mark as brainliest
You might be interested in
Find K if K divided by 64 equals 4
pshichka [43]

Solve:

\frac{k}{64}=4

We need to isolate k, so multiply both sides by the denominator, which is 64. When we do that, the fraction will cancel and we get:

k=256

If you want to check, plug in your answer to the original equation and see if it is true:

\frac{256}{64}=4

4=4

This statement is true, so k=256.

4 0
3 years ago
Read 2 more answers
What are punctuation marks used to set off words that define or explain another word?
levacccp [35]

Answer:

parentheses

Step-by-step explanation:

Hope this helps <3

4 0
3 years ago
Which of the following is an equivalent expression to the expression a1/3 / a1/4
mixas84 [53]

Answer:

Option A :- \sf {a}^{\frac{1}{12}}

Step-by-step explanation:

\hookrightarrow \sf \:  \frac{ {a}^{ \frac{1}{3} } }{ {a}^{ \frac{1}{4} } }

Simplify the expression

\hookrightarrow \sf \:  {a}^{ \frac{1}{3} -  \frac{1}{4}  }

Transform the Expression

\hookrightarrow \sf \:  {a}^{ \frac{4 - 3}{12}  }

Calculate

\hookrightarrow \sf {a}^{\frac{1}{12}}

4 0
2 years ago
Read 2 more answers
What is 2xy-3yz+5+2yz-xy
melomori [17]

To simplify this expression, we are going to combine like terms.


First, we can see that we have two terms with the variables xy being multiplied together, 2xy and -xy. Together, these add to xy, so our expression is now:

xy - 3yz + 5 + 2yz


We also have two terms with yz, -3yz and 2yz. Together, these add to -yz, so our expression is now:

xy - yz + 5


Our final expression is xy - yz + 5.

6 0
3 years ago
A survey question revealed that at a particular college 87 percent of students worked at least sometime during their undergradua
Elanso [62]

Answer:

The correct option is A. 198 degrees

Step-by-step explanation:

Consider the provided information.

87 percent of students worked at least sometime during their undergraduate career and 13 percent did not work at all.

Another question showed that 32 percent of the students worked throughout their undergraduate career.

87 percent  of the students worked at least sometime during the college. Out of them 32% worked throughout the college.

Therefore, the students who worked sometime during their undergraduate career, but not throughout are:

(87-32)% = 55% .

As we know the angle measure in circle  is 360 degrees.

55% of 360° is:

\frac{55}{100}\times360= 198

Hence, the measure of central angle would be 198 degrees

Therefore, the correct option is A. 198 degrees

8 0
4 years ago
Other questions:
  • Which of the following would have a scale factor with an absolute value greater than 1?
    13·1 answer
  • 20 - 9w = 4(15 - w) solve for w​
    11·2 answers
  • How many times can 36 go into 79
    14·1 answer
  • If -11 + N = -11, then N is the _____.
    8·2 answers
  • Mrs. People purchased Sandwiches at 2 for $6.00 and Donuts for $2.00 a package. She spent $19 for a total of 7 items. How many s
    14·1 answer
  • You receive wallet size photos of your school picture. The photo is 2.5" x 3.5"  you decided dilate the photo to 5" x 7" at th
    5·2 answers
  • Greg bought 18 4/5 gallons of gas. What decimal should the meter on the gas pump read?
    10·1 answer
  • Simplify the following expression
    9·1 answer
  • If a pie is divided evenly into thirds, what can you infer about each slice?
    7·1 answer
  • a community center is trying to raise $1680 to purchase exercise equipment. the center is hoping to receive equal contributions
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!