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natta225 [31]
3 years ago
8

Plz answer this is very important

Mathematics
2 answers:
mezya [45]3 years ago
5 0
Circumference of a circle=2πr
2×π×19=38π≈119.38≈119.4
Hope my answer helped u :)
NikAS [45]3 years ago
3 0
P=2₶R
P=2*3.14*19cm = 119.38cm
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-7b&lt; -35<br> =less than or equal two
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Answer:

b>5

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Step-by-step explanation:

divide -35 by -5, and since you are dividing by a negative, the sign flips

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Lettuce is packed four to a box . If there are 3.5 boxes of Lettuce in the cooler , how many bags of Lettuce would there be
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What is the measure of the central angle of a circle with radius 15ft that intercepts a 10ft arc
svetlana [45]
Radius = 15 feet
circumference = 2 * PI * 15 = <span> <span> <span> 94.25 </span></span></span>feet
the length of the arc is 10 feet
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5 0
3 years ago
Mass of Weight(C)
Stolb23 [73]
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3 0
3 years ago
I need help PLEASE!!!
Stella [2.4K]

9514 1404 393

Answer:

  y = -4/3x +23/2

Step-by-step explanation:

The tangent of interest is perpendicular to the radius at the given point on the circle. To find the perpendicular, it helps to know the slope of the radius segment. To find that, we need the center of the circle.

The center of the circle can be found by completing the square for each variable.

  (x^2 -2x) +(y^2 +4y) = 20

  (x^2 -2x +1) +(y^2 +4y +4) = 20 +1 +4

  (x -1)^2 +(y +2)^2 = 25

Comparing this equation to the standard form equation for a circle, we can find the center.

  (x -h)^2 +(y -k)^2 = r^2 . . . . . . . circle of radius r centered at (h, k)

The center of circle P is (1, -2).

__

The slope m' of the line segment between (1, -2) and (5, 1) is given by ...

  m' = (y2 -y1)/(x2 -x1)

  m' = (1 -(-2))/(5 -1) = 3/4

The slope m of the perpendicular line is the opposite reciprocal of this, so is ...

  m = -1/m' = -1/(3/4) = -4/3

The y-intercept of the desired line can be found from ...

  b = y -mx . . . . . . . for m=-4/3 and (x, y) = (5, 1)

  b = 1 -(-4/3)(5) = 23/3

Then the equation of tangent line AB is ...

  y = mx +b

  y = -4/3x +23/3

6 0
2 years ago
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