What is the area of the rectangle ABCD shown below? (Use the distance formula.) A = bh

Circle O is shown. Line segments B O and O C are radii. Point A is on the circle and is not within angle B O C.

Paha777 [63]

The ratio of major to minor arc = 2 : 1

What is a Circle?

A circle is the locus of a point such that its distance from a fixed point (center) is always constant.

Calculation

The length of an arc (L) with center angle θ is given by:

L = (θ/360) * 2πr

where r is the radius.

Putting the values in the above formula.

For the major arc:

L = (240/360) * 2πr

For the major arc:

l = ((360-240)/360) * 2πr

l = (120/360) * 2πr

The ratio of major to minor arc = [(240/360) * 2πr] / [(120/360) *2πr] = 2 : 1

The ratio of major to minor arc = 2 : 1.

Learn more about the circle here:

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5 0

2 years ago

determine the average rate of change of the function between the given variables h(x) = x; x=a, x=a+h

Alecsey [184]

Answer:

the average rate of change is 4.

Step-by-step explanation:

Find the average rate of change of f(x)=x^2 on the interval [1,3].

The average rate of change of f(x) on the interval [a,b] is f(b)−f(a)/b−a.

We have that a=1, b=3, f(x)=x^2.

Thus, f(b)−f(a)/b−a=((3))^2−(((1))^2)/3−(1) = 4.

6 0

3 years ago

Juanita says that 3.5[4d - (2) (1.5)] and 2[7d - (5)(1.05)] are equivalent. Is Juanita correct? Explain your reasoning.

valkas [14]

Answer:

Yes

Step-by-step explanation:

3.5 [4d - 2*1.5] = 3.5*4d - 3.5*2*1.5

= 14d - 10.5

2*[7d - 5*1.05] = 2*7d - 2*5*1.05

= 14d - 10.5

When we are simplifying both the expression using distributive property, we get the same expression at the end.

8 0

3 years ago

Karen runs a print shop that makes posters for large companies. It is a very competitive business. The market price is currently

kumpel [21]

AFC = FC / Quantity printed

So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 
Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 
Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 

ATC = TC / Quantity printed 

where TC = FC + Variable C * Quantity printed 

If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 
ATC = 2,000,250/1000 = 2000.25 

If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 
ATC = 3,200,250/2000 = 1600.125 

If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 
ATC = 11,200,250/10000 = 1120.025

7 0

3 years ago

If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (

AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is $\frac{1}{12}$

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

$P=\frac{3}{36}$

$P=\frac{1}{12}$

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is $\frac{1}{12}$

5 0

3 years ago