Question

Find an equation of the circle whose diameter has endpoints , (−6,−1) and (2,3).

Answer 1

Answer:

first... You think and Conceptualize

A diameter divides a circle into equal halves

We're given the end points of the Diameter.

With this we can fine the Center of the circle.

The End Points are

(-6, -1) and ( 2, 3)

Half-way through the diameter gives the center of the circle

So We'd apply the Mid-Point formula to get the co-ordinate of the center.

X= x₁ + x₂/2 , Y = y₁ + y₂/2

X = -6 + 2/2, Y = -1 + 3/2

X= -2. Y = 1

The Midpoint is (-2, 1)

The Radius would be the distance between the center and a point on the circumference.

We already have 2 points of the circumference (Which are the endpoints of the diameter).

So we can pick any of them arbitrarily.

I'd go with (2,3)

So We'd apply the distance between Points formula to get the magnitude of the radius

(-2,1) (2,3)

D = √(x₁ - x₂)² + (y₁ - y₂)²

D = √(-2-2)² + (1-3)²

D=√(-4)² + (-2)²

D=√20.

Our Radius is √20.

Equation of Circle =

(x-h)² + (y-k)² = r²

Where h and k are the center of the circle(-2,1)

(x-(-2))² + ( y - 1 )²= (√20)²

(x + 2)² + ( y - 1)² = 20

Our Answer

(x + 2)² + (y - 1)² = 20.

This should be it.

Have a great day!