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vesna_86 [32]
4 years ago
7

Is that 2x squared + 5x? Correct me if I'm wrong.

Mathematics
2 answers:
Svet_ta [14]4 years ago
6 0
The answer would be 5x2*
natulia [17]4 years ago
4 0
Well, what I would do is divide it into two shapes. Cut off the bottom part to make two separate quadrilaterals, and you'd have a square with sides of x. So the area would be x^2. Then, for the remaining piece (rectangle), add the x from the square bit to 5 for one side, and the other side would be x. So you'd have 5x * x, which equals 5x^2. Add the two separate area's together to get the total area, which would give you 6x^2. Hope that helped! :)
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What should be added to 3 to make the sum 0?
Phoenix [80]

Answer:

-3

Step-by-step explanation:

3+x=0

subtract 3 from 3, 0

subtract 3 from 0, -3

5 0
4 years ago
Read 2 more answers
A problem is given to three students A,B and C whose chances of solving 1/2, 1/3 and 1/4 respectively. What is the probability t
tatuchka [14]

Answer:

because

1/2+1/3+1/4

1/2x6+1/3x4+1/4x3

1/12+1/12+1/12

1+1+1/12

3/12

1/4

1:4 so,their is a proability that the problem will be solved.

5 0
3 years ago
From 12x ­- 6y + 9z subtract -x­ -3z + 6y . A)   12z ­- 13x -­ 12y B)   13x + 12y + 12z C)  - ­13x -­ 12y ­- 12z D)   13x -­ 12y
seraphim [82]
12x - 6y + 9z - (-x - 3z + 6y) = 12x - 6y + 9z + x + 3z - 6y = 13x - 12y + 12z
4 0
3 years ago
Juan is considering two gym membership options. Gym A charges an enrollment fee of $250 plus $19 per month. Gym B charges an enr
kakasveta [241]

Answer:

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6 0
3 years ago
Solve.<br><br> x + 5 ≥ 12 or <br> x<br> 9<br> &lt; 0
Andreyy89
<h3>I'll teach you how to solve x + 5 ≥ 12 or x*9< 0</h3>

--------------------------------------------------------------

x + 5 ≥ 12 or x*9< 0

First lets solve x+5>12:

Subtract 5 from both sides:

x+5-5>12-5

Simplify:

x> 7

Now lets solve x*9< 0:

Divide both sides by 9:

x*9/9 < 0/9

SImplify:

X<0

Combine the intervals:

x \geq 7 or x < 0

Your Answer Is x \geq 7 or x < 0

plz mark me as brainliest :)

7 0
3 years ago
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