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lisov135 [29]
3 years ago
13

What is the amplitude of sin ?

Mathematics
1 answer:
sp2606 [1]3 years ago
6 0

You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.

Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.

For sine function, can be written as:

\displaystyle \large{ y = A \sin(bx  -  c) + d}

  • A = amplitude
  • b = period = 2π/b
  • c = horizontal shift
  • d = vertical shift

I am not able to provide an attachment for an easy view but I will try my best!

We know that amplitude or A is a distance from baseline/midline to the max-min point.

Let's see the example of equation:

\displaystyle \large{y = 2 \sin x}

Refer to the equation above:

  • Amplitude = 2
  • b = 1 and therefore, period = 2π/1 = 2π
  • c = 0
  • d = 0

Thus, the baseline or midline is y = 0 or x-axis.

You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.

So to conclude or say this:

If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.

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Answer:

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Step-by-step explanation:

To find out the area we should have to redraw the figure having nomenclature ABCDE and join BD. Thus we have a rectangle ABDE and a triangle BCD.

The new figure is in the attachment.

Given,

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Length of BD = length of AE = 7 cm

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Area of ABCDE = Area of ABDE + Area of BCD = 56+10.5=66.5\ cm^2

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